Bob invested one-half of his savings in a bond that paid simple interest for 2 years and received $550 as interest. He invested the remaining in a bond that paid compound interest (compounded annually) for the same 2 years at the same rate of interest and received $605 as interest. What was the annual rate of interest?
(A) 5%
(B) 10%
(C) 12%
(D) 15%
(E) 20%
Answer: E
Source: Veritas Prep
Bob invested one-half of his savings in a bond that paid simple interest for 2 years and received $550 as interest. He
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Simple interest for 2 years = $550
Simple interest for 1 year = 550/2 = $275
Investing in another bond in which the interest is compounded annually and received $605
Therefore, interest gotten from 1st year = 605 - 550 = $55
Let the rate of interest = R
R% of 1 year simple interest = $55
R% of 275 = 55
R/100 * 275 = 55
275R/275 = 5500/275
R = 20%
Answer = E
Simple interest for 1 year = 550/2 = $275
Investing in another bond in which the interest is compounded annually and received $605
Therefore, interest gotten from 1st year = 605 - 550 = $55
Let the rate of interest = R
R% of 1 year simple interest = $55
R% of 275 = 55
R/100 * 275 = 55
275R/275 = 5500/275
R = 20%
Answer = E
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Let the amount invested in each bond = $100M7MBA wrote: ↑Thu Aug 20, 2020 9:00 amBob invested one-half of his savings in a bond that paid simple interest for 2 years and received $550 as interest. He invested the remaining in a bond that paid compound interest (compounded annually) for the same 2 years at the same rate of interest and received $605 as interest. What was the annual rate of interest?
(A) 5%
(B) 10%
(C) 12%
(D) 15%
(E) 20%
We can PLUG IN THE ANSWERS, which represent the simple interest.
When the correct answer is plugged in:
(simple interest)/(compound interest) = 550/605 = 110/121 = 10/11
The numerator of the blue fraction suggests that the correct answer is likely to be a multiple of 10.
B: 10%
Simple interest:
First-year interest = 10% of 100 = 10
Second-year interest = 10% of 100 = 10
Total interest = 10+10 = 20
Compound interest:
First-year interest = 10% of 100 = 10
Amount at the end of the first year = 100+10 = 110
Second-year interest = 10% of 110 = 11
Total interest = 10+11 = 21
Resulting ratio:
simple/compound = 20/21
The required ratio is not yielded.
Eliminate B.
E: 20%
Simple interest:
First-year interest = 20% of 100 = 20
Second-year interest = 20% of 100 = 20
Total interest = 20+20 = 40
Compound interest:
First-year interest = 20% of 100 = 20
Amount at the end of the first year = 100+20 = 120
Second-year interest = 20% of 120 = 24
Total interest = 20+24 = 44
Resulting ratio:
simple/compound = 40/44 = 10/11
Success!
The correct answer is E.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
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Student Review #3