Bill buys two types of soda. He buys \(m\) bottles of Brand \(A\) at \(\$0.50\) each. He buys \(n\) bottles of Brand \(B\) at \(\$0.60\) each. What is Bill’s average cost in cents for a bottle of soda, in terms of \(m\) and \(n?\)
A. \(\dfrac{0.5m+0.6n}{m+n}\)
B. \(\dfrac{m+n}{110}\)
C. \(\dfrac{1.1}{m+n}\)
D. \(\dfrac{50m+60n}{m+n}\)
E. \(\dfrac{50m+60n}{mn}\)
Answer: D
Source: Princeton Review
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Bill buys two types of soda. He buys \(m\) bottles of Brand \(A\) at \(\$0.50\) each. He buys \(n\) bottles of Brand
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Solution:M7MBA wrote: ↑Thu Nov 19, 2020 9:15 amBill buys two types of soda. He buys \(m\) bottles of Brand \(A\) at \(\$0.50\) each. He buys \(n\) bottles of Brand \(B\) at \(\$0.60\) each. What is Bill’s average cost in cents for a bottle of soda, in terms of \(m\) and \(n?\)
A. \(\dfrac{0.5m+0.6n}{m+n}\)
B. \(\dfrac{m+n}{110}\)
C. \(\dfrac{1.1}{m+n}\)
D. \(\dfrac{50m+60n}{m+n}\)
E. \(\dfrac{50m+60n}{mn}\)
Answer: D
Note that $0.50 is 50 cents and $0.60 is 60 cents. Thus, the total cost of the (m + n) bottles of soda, in cents, is 50m + 60n. Thus, the average cost is:
(50m + 60n) / (m + n)
Answer: D
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