If a and b are nonzero numbers on the number line, is 0 between a and b?
(1) The distance between 0 and a is greater than the distance between 0 and b.
(2) The sum of the distances between 0 and a and between 0 and b is greater than the distance between 0 and the sum of a + b.
Answer should be "Statement (2) alone is sufficient.
Between A and B
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- simplyjat
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Don't say "Answer should be", its confusing. Its better to say "my answer" and "official answer"...
Coming back to the question, when dealing with number line and distances, always think absolute values.
1) |a| > |b|
2) |a| + |b| > |a + b|
Here the second statement is true only when a and b have different sign, because with same signs |a| + |b| = |a + b|.
So we have two numbers with different signs 0 will always be in between...
Coming back to the question, when dealing with number line and distances, always think absolute values.
1) |a| > |b|
2) |a| + |b| > |a + b|
Here the second statement is true only when a and b have different sign, because with same signs |a| + |b| = |a + b|.
So we have two numbers with different signs 0 will always be in between...
simplyjat
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Simplyjat has done excellent job in explaining..kaf wrote:Can someone please elaborate on this solution
thanks
I will try add my 2c.
Try plugging numbers to the absolute equation mentioned above.
But whenever u plug in numbers assume they are numbers on a numberline.
And whenever u see a absolute mentioned, immediately think of as a distance of that number from the origin.
Actually, u can see Stewart/Ian's comments on a previous Absolute!!! problem.
- gmat740
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It is a good idea to draw a number line:
two cases are possible:
a..........b.........0
or a.........0........b
(I) this one talks about a.........0........b
but what about a..........b.........0
distance between 0 and a> distance between 0 and b
so Insuff
(II)clearly speaks of this:
a.........0........b
the other case will not be satisfied
So (II) Suff
Hence B
Hope this helps
Karan
two cases are possible:
a..........b.........0
or a.........0........b
(I) this one talks about a.........0........b
but what about a..........b.........0
distance between 0 and a> distance between 0 and b
so Insuff
(II)clearly speaks of this:
a.........0........b
the other case will not be satisfied
So (II) Suff
Hence B
Hope this helps
Karan
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karan,
I did the same thing. though can u explain it with #s?
I'm guessing that would make it quicker and simpler.
I did the same thing. though can u explain it with #s?
I'm guessing that would make it quicker and simpler.
gmat740 wrote:It is a good idea to draw a number line:
two cases are possible:
a..........b.........0
or a.........0........b
(I) this one talks about a.........0........b
but what about a..........b.........0
distance between 0 and a> distance between 0 and b
so Insuff
(II)clearly speaks of this:
a.........0........b
the other case will not be satisfied
So (II) Suff
Hence B
Hope this helps
Karan
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Also what would be the difficulty level of this Q? and how much time should one spend on this Q?
Can someone break down the second statement, please?
Can someone break down the second statement, please?
https://www.beatthegmat.com/a-and-b-on-t ... 37331.html
This thread has a good explanation for the answer
This thread has a good explanation for the answer
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ohh my answer is B too,adi wrote:If a and b are nonzero numbers on the number line, is 0 between a and b?
(1) The distance between 0 and a is greater than the distance between 0 and b.
(2) The sum of the distances between 0 and a and between 0 and b is greater than the distance between 0 and the sum of a + b.
Answer should be "Statement (2) alone is sufficient.
what is the OA? " answer should be statement 2 alone is sufficient" is your answer or OA?
- GMATGuruNY
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Absolute value means distance from 0.adi wrote:If a and b are nonzero numbers on the number line, is 0 between a and b?
(1) The distance between 0 and a is greater than the distance between 0 and b.
(2) The sum of the distances between 0 and a and between 0 and b is greater than the distance between 0 and the sum of a + b.
Answer should be "Statement (2) alone is sufficient.
Statement 1: |a| > |b|
Plug in a=3, b=2.
This works, because |3| > |2|.
Is 0 between 3 and 2? No.
Plug in a= -3, b=2.
This works, because |-3| > |2|.
Is 0 between -3 and 2? Yes.
Since the answer can be both No and Yes, insufficient.
Statement 2: |a| + |b| > |a+b|
Plug in a=3, b=2.
|3| + |2| > |3+2|. Doesn't work, because |3| + |2| = |3+2|.
This shows us that a and b cannot both be positive.
Plug in a = -3, b = -2.
|-3| + |-2| > |-3 + (-2)|. Doesn't work, because |-3| + |-2| = |-3 + (-2)|.
This shows us that a and b cannot both be negative.
Since a and b cannot both be positive -- nor can they both be negative -- 0 must be between them. Sufficient.
The correct answer is B.
For example:
Plug in a=-3, b=2.
This works, because |-3| + |2| > |-3+2|.
Is 0 between -3 and 2? Yes.
Plug in a=3, b=-2.
This works, becuase |3| + |-2| > |3+(-2)|.
Is 0 between 3 and -2? Yes.
Since the answer is consistently Yes, sufficient.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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