Average problem

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Average problem

by phoenix9801 » Thu May 31, 2012 7:59 am
The average (arithmetic mean) of 20, 60, and 100 is 10 more than the average of 40, 80, and which of the following?

A) 110
B) 90
C) 70
D) 50
E) 30

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by shankar.ashwin » Thu May 31, 2012 9:08 am
Average of (20,60,100) = 180/3 = 60

Given 60 is 10 more than average of (40,80,x)

(or) Avg of (40,80,x) = 50

120+x = 3(50)

[spoiler]x = 30 (E)[/spoiler]

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by massi2884 » Thu May 31, 2012 9:10 am
Avg. of 20, 60, and 100 is (100+20+60)/3 = 60

60 is 10 more than 50

If 50 is the avg. of 3 numbers, their sum is 3x50 = 150

What is missing to 40 + 80 to get to 150 is 30 (E)