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Arithmetic

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Arithmetic

by swerve » Thu Oct 01, 2020 10:01 am

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B

C

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E

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If the sum of three consecutive integers is k, then which of the following is a possible value of k?

A. 199
B. 200
C. 201
D. 202
E. 203

The OA is C

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Re: Arithmetic

by psarma » Thu Oct 01, 2020 3:33 pm
Let the 3 consecutive integers be n, n+1 and n+2
Given, n+(n+1)+(n+2)=k
or 3n+3=k
or 3(n+1)=k
i.e k is thus a multiple of 3.

From the options given, only 201 is a multiple of 3.

Answer C.
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Re: Arithmetic

by Scott@TargetTestPrep » Tue Oct 06, 2020 3:17 am
swerve wrote: ↑
Thu Oct 01, 2020 10:01 am
 If the sum of three consecutive integers is k, then which of the following is a possible value of k?

A. 199
B. 200
C. 201
D. 202
E. 203

The OA is C

Solution:

Since the sum of any three consecutive integers must be a multiple of 3 (e.g., 1 + 2 + 3 = 6; 8 + 9 + 10 = 27, etc.), then k could be 201 (notice that it’s the only number in the given choices that is a multiple of 3).

Answer: C

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