This is from OG 13 #117 in Problem Solving:
If N = 3^8  2^8, which of the following is NOT a factor of n?
A) 97
B) 65
C) 35
D) 13
E) 5
OA: C
The book posts a pretty obscure way to solve, would like to hear others opinions on this question.
Arithmetic  Properties of Numbers: If n = ...
This topic has expert replies
 neelgandham
 Community Manager
 Posts: 1060
 Joined: Fri May 13, 2011 6:46 am
 Location: Utrecht, The Netherlands
 Thanked: 318 times
 Followed by:52 members
If N = 3^8  2^8, which of the following is NOT a factor of n?
3^8  2^8 = (3^42^4)(3^4+2^4)  a^2 b^2 = (a+b)*(ab)
3^8  2^8 = (3^22^2)(3^2+2^2)(3^4+2^4)  a^2 b^2 = (a+b)*(ab)
3^8  2^8 = (32)(3+2)(3^2+2^2)(3^4+2^4)
3^8  2^8 = (1)(5)(13)(97), so 97,65(13*5),13,5 are factors of 3^8  2^8. The only number left is 35, which isn't a factor of 3^8  2^8
3^8  2^8 = (3^42^4)(3^4+2^4)  a^2 b^2 = (a+b)*(ab)
3^8  2^8 = (3^22^2)(3^2+2^2)(3^4+2^4)  a^2 b^2 = (a+b)*(ab)
3^8  2^8 = (32)(3+2)(3^2+2^2)(3^4+2^4)
3^8  2^8 = (1)(5)(13)(97), so 97,65(13*5),13,5 are factors of 3^8  2^8. The only number left is 35, which isn't a factor of 3^8  2^8
Anil Gandham
Welcome to BEATtheGMAT  Photography  Getting Started  BTG Community rules  MBA Watch
Check out GMAT Prep Now's online course at https://www.gmatprepnow.com/
Welcome to BEATtheGMAT  Photography  Getting Started  BTG Community rules  MBA Watch
Check out GMAT Prep Now's online course at https://www.gmatprepnow.com/
 LalaB
 Master  Next Rank: 500 Posts
 Posts: 425
 Joined: Wed Dec 08, 2010 9:00 am
 Thanked: 56 times
 Followed by:7 members
 GMAT Score:690
3^8  2^8=(3^42^4)(3^4+2^4)=
=(8116)(81+16)=65*97 (a and b are out)
65*97=5*13*97 (d and E are out)
answ is C
=(8116)(81+16)=65*97 (a and b are out)
65*97=5*13*97 (d and E are out)
answ is C
Happy are those who dream dreams and are ready to pay the price to make them come true.(c)
In order to succeed, your desire for success should be greater than your fear of failure.(c)
In order to succeed, your desire for success should be greater than your fear of failure.(c)
GMAT/MBA Expert
 Scott@TargetTestPrep
 GMAT Instructor
 Posts: 7436
 Joined: Sat Apr 25, 2015 10:56 am
 Location: Los Angeles, CA
 Thanked: 43 times
 Followed by:29 members
Solution:wied81 wrote:This is from OG 13 #117 in Problem Solving:
If N = 3^8  2^8, which of the following is NOT a factor of n?
A) 97
B) 65
C) 35
D) 13
E) 5
OA: C
The book posts a pretty obscure way to solve, would like to hear others opinions on this question.
It is very unlikely that a problem would require us to calculate 3^8 or 2^8, so we should approach this problem not as an arithmetic question but as an algebraic one.
The first thing we should recognize is that we are being tested on the algebraic factoring technique called the "difference of squares." Recall that the general form of the difference of squares is:
x^2  y^2 = (x + y)(x  y)
Similarly, we can treat 3^8  2^8 as a difference of squares, which can be expressed as:
n = (3^4 + 2^4)(3^4  2^4)
We can further factor 3^4  2^4 as an additional difference of squares, which can be expressed as:
(3^2 + 2^2)(3^2  2^2)
This finally gives us:
n = 3^8  2^8 = (3^4 + 2^4)(3^2 + 2^2)(3^2  2^2)
The numbers are now easy to calculate:
n = (81 + 16)(9 + 4)(9  4)
n = (97)(13)(5)
We are being asked which of the answer choices is NOT a factor of n, which we have determined to be equal to the product (97)(13)(5). So we must find the answer choice that does not evenly divide into (97)(13)(5).
We immediately see that 97, 13 and 5 are all factors of (97)(13)(5).
This leaves us with 65 and 35. Notice that (97)(13)(5) = (97)(65). Thus, 65 also is a factor of n. Only 35 is not.
Answer: C
Scott WoodburyStewart
Founder and CEO
[email protected]
See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews
GMAT/MBA Expert
 Brent@GMATPrepNow
 GMAT Instructor
 Posts: 16207
 Joined: Mon Dec 08, 2008 6:26 pm
 Location: Vancouver, BC
 Thanked: 5254 times
 Followed by:1268 members
 GMAT Score:770
I want to add something about the concept of algebraic manipulations without variables:
The GMAT loves to test our algebra skills (like factoring), HOWEVER many students associate algebra with variables only, so they don't see that we can apply algebraic principles to numbers as well (which should make sense, since those variables are, indeed, representing numbers).
So, for example, many students are fine with the following:
 Factoring 6x + 3 to get 3(2x + 1)
 Factoring 6xâ�µ + 2xÂ³ + 8xÂ² to get 2xÂ²(3xÂ³ + x + 4)
 Factoring xÂ² + 5x + 6 to get (x + 2)(x + 3)
 Factoring xÂ²  yÂ² to get (x + y)(x  y)
On the GMAT, we need to recognize that we can also factor expressions that have no variables.
So, for example, a GMAT question might ask us to evaluate 54Â²  53Â²
If we recognize that this is a difference of squares in the form xÂ²  yÂ², we can factor it to get:
54Â²  53Â² = (54 + 53)(54  53) = (107)(1) = 107
Likewise, the expression 2Â¹â�°â�°  2â�¹â�¶ is no different from xÂ¹â�°â�°  xâ�¹â�¶
xÂ¹â�°â�°  xâ�¹â�¶ = xâ�¹â�¶(xâ�´  1) in the exact same way that 2Â¹â�°â�°  2â�¹â�¶ = 2â�¹â�¶(2â�´  1)
Cheers,
Brent
The GMAT loves to test our algebra skills (like factoring), HOWEVER many students associate algebra with variables only, so they don't see that we can apply algebraic principles to numbers as well (which should make sense, since those variables are, indeed, representing numbers).
So, for example, many students are fine with the following:
 Factoring 6x + 3 to get 3(2x + 1)
 Factoring 6xâ�µ + 2xÂ³ + 8xÂ² to get 2xÂ²(3xÂ³ + x + 4)
 Factoring xÂ² + 5x + 6 to get (x + 2)(x + 3)
 Factoring xÂ²  yÂ² to get (x + y)(x  y)
On the GMAT, we need to recognize that we can also factor expressions that have no variables.
So, for example, a GMAT question might ask us to evaluate 54Â²  53Â²
If we recognize that this is a difference of squares in the form xÂ²  yÂ², we can factor it to get:
54Â²  53Â² = (54 + 53)(54  53) = (107)(1) = 107
Likewise, the expression 2Â¹â�°â�°  2â�¹â�¶ is no different from xÂ¹â�°â�°  xâ�¹â�¶
xÂ¹â�°â�°  xâ�¹â�¶ = xâ�¹â�¶(xâ�´  1) in the exact same way that 2Â¹â�°â�°  2â�¹â�¶ = 2â�¹â�¶(2â�´  1)
Cheers,
Brent

 GMAT Instructor
 Posts: 2630
 Joined: Wed Sep 12, 2012 3:32 pm
 Location: East Bay all the way
 Thanked: 625 times
 Followed by:119 members
 GMAT Score:780
Here's an approach that doesn't involve difference of squares.
If a number divides by 65, it must divide by 13 and by 5. So D and E *CANNOT* be the answers: if the number is not divisible by 5, it is also not divisible by 65. (Same logic for 13 and 65.) Now that we know the answer divides by 5 and 13, it must also divide by 65, so B CANNOT be the answer.
Now we'll consider A and C. Since we know our number divides by 5, it will divide by 35 if and only if our number also divides by 7. (This is because 35 = 5 * 7).
At this point, we recall that 3â�¸  2â�¸ will divide by 7 if 3â�¸ and 2â�¸ have the same remainder when divided by 7. 2â�¸ = 256, which has a remainder of 4 when divided by 7. 3â�¸ = 6561, which has a remainder of 2.
So our number doesn't divide by 7, and hence can't divide by 35. We're done, and we don't need to bother testing A.
If a number divides by 65, it must divide by 13 and by 5. So D and E *CANNOT* be the answers: if the number is not divisible by 5, it is also not divisible by 65. (Same logic for 13 and 65.) Now that we know the answer divides by 5 and 13, it must also divide by 65, so B CANNOT be the answer.
Now we'll consider A and C. Since we know our number divides by 5, it will divide by 35 if and only if our number also divides by 7. (This is because 35 = 5 * 7).
At this point, we recall that 3â�¸  2â�¸ will divide by 7 if 3â�¸ and 2â�¸ have the same remainder when divided by 7. 2â�¸ = 256, which has a remainder of 4 when divided by 7. 3â�¸ = 6561, which has a remainder of 2.
So our number doesn't divide by 7, and hence can't divide by 35. We're done, and we don't need to bother testing A.

 Legendary Member
 Posts: 518
 Joined: Tue May 12, 2015 8:25 pm
 Thanked: 10 times
Factoring Formula  xÂ²  yÂ² to get (x + y)(x  y) is the key to solve this question.
35 is the answer.
35 is the answer.
GMAT/MBA Expert
 [email protected]
 Elite Legendary Member
 Posts: 10392
 Joined: Sun Jun 23, 2013 6:38 pm
 Location: Palo Alto, CA
 Thanked: 2867 times
 Followed by:511 members
 GMAT Score:800
Hi All,
We’re told that N = 3^8 – 2^8. We’re asked which of the follow 5 numbers is NOT a factor of N. The GMAT would NEVER require that you calculate that overall value, so there must be a way to ‘simplify’ that equation. Since it includes Exponents and SUBTRACTION of two values raised to the SAME EVEN power, we should be on the lookout for Classic Quadratics…
You’re probably familiar with X^2 – Y^2 (since that is one of the common “Classic” Quadratics… X^2 – Y^2 = (X + Y)(X – Y)). Similar Quadratics exist for X^4 – Y^4, X^6 – Y^6 and X^8 – Y^8. Quadratic rules apply whether there are variables or numbers involved, so we can replace the X and Y with the “3” and “2”, respectively in the given calculation…
3^8 – 2^8 =
(3^4 + 2^4)(3^4 – 2^4)
We can then ‘factor down’ the 2nd part of that step…
(3^4 + 2^4)(3^4 – 2^4) =
(3^4 + 2^4)(3^2 + 2^2)(3^2 – 2^2)
And then ‘factor down’ the 3rd part of that step…
(3^4 + 2^4)(3^2 + 2^2)(3 + 2)(3  2) =
This gives us…
(81+16)(9+4)(5)(1)
(97)(13)(5)(1)
With these results, we can clearly eliminate Answers A, D and E. By multiplying the 13 and 5, we get (13)(5) = 65, so that is ALSO a factor – and we can eliminate Answer B.
Final Answer: C
GMAT Assassins aren’t born, they’re made,
Rich
We’re told that N = 3^8 – 2^8. We’re asked which of the follow 5 numbers is NOT a factor of N. The GMAT would NEVER require that you calculate that overall value, so there must be a way to ‘simplify’ that equation. Since it includes Exponents and SUBTRACTION of two values raised to the SAME EVEN power, we should be on the lookout for Classic Quadratics…
You’re probably familiar with X^2 – Y^2 (since that is one of the common “Classic” Quadratics… X^2 – Y^2 = (X + Y)(X – Y)). Similar Quadratics exist for X^4 – Y^4, X^6 – Y^6 and X^8 – Y^8. Quadratic rules apply whether there are variables or numbers involved, so we can replace the X and Y with the “3” and “2”, respectively in the given calculation…
3^8 – 2^8 =
(3^4 + 2^4)(3^4 – 2^4)
We can then ‘factor down’ the 2nd part of that step…
(3^4 + 2^4)(3^4 – 2^4) =
(3^4 + 2^4)(3^2 + 2^2)(3^2 – 2^2)
And then ‘factor down’ the 3rd part of that step…
(3^4 + 2^4)(3^2 + 2^2)(3 + 2)(3  2) =
This gives us…
(81+16)(9+4)(5)(1)
(97)(13)(5)(1)
With these results, we can clearly eliminate Answers A, D and E. By multiplying the 13 and 5, we get (13)(5) = 65, so that is ALSO a factor – and we can eliminate Answer B.
Final Answer: C
GMAT Assassins aren’t born, they’re made,
Rich