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## area of equilateral triangle "shortcut" tidbit

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### area of equilateral triangle "shortcut" tidbit

by jzw » Mon Mar 19, 2012 7:00 am
Only use it if you get why it is this way so that you don't accidentally apply it to the wrong kind of triangle.

Area of Equilateral Triangle = âˆš3/4 * X^2.

Why?

1. An equilateral triangle is one where all sides are equal to each other (let's call each side "X" since it can be any number) and all angles are equal to 60 degrees.

2. To make an equilateral triangle into two 30-60-90 triangles, we draw a line from the center of one of the bases until it reaches the top (angle) from the perspective of "that base" being the bottom of the triangle.

3. In a 30-60-90 triangle, the side between 30 and 60 is equal to 2X, the side that divides the two triangles becomes the height and is equal to Xâˆš3 and the side between 90 and 60 becomes X. (Remember that by drawing the line which becomes the height we created a 90 degree angle since those lines are perpendicular.)

4. So the area of this triangle would be, like any other, B*H/2. So that's X*Xâˆš3/2

5. Now - in the original triangle, remember that each side was equal. When we divided it in half by adding the line to represent the height (Xâˆš3) each of the two "new" bases became 1/2 of the former base, which can be represented by X/2. To properly represent this throughout the triangle, the side between the 30 and the 60 degrees changes from 2X to X, and the height, Xâˆš3 becomes Xâˆš3/2.

6. So the area (base*height/2) can be rewritten as X/2 * Xâˆš3/2. This can be simplified to âˆš3/4 * X^2.

The point of knowing the shortcut for those that can use it is to potentially help save time, depending on what information in your geometry question you are given on the GMAT, you might be able to just plug it in here instead of having to separately split the triangle, recalculate the lengths of the smaller bases...

Hope this helps and isn't written confusing.
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