I dont undersatnd this
th answer is squared
please help me!
applied circumference problem..finding distance?
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The distance between the centre of the two wheels is the same as the horizontal part of the belt.
The part that is touching each wheel is equal to half the diameter for each one.
Answer = (Total length - 2 x half circumference)/2
= (15 - 2 x pi x 0.5)/2
= (15 - pi)/2 A.
The part that is touching each wheel is equal to half the diameter for each one.
Answer = (Total length - 2 x half circumference)/2
= (15 - 2 x pi x 0.5)/2
= (15 - pi)/2 A.
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- Senior | Next Rank: 100 Posts
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why did u divide by 2
i get that the horizontal line is 15
and its touching 1/2 of the circumference of each circle
but i stil dont get how this is formed 15-pi/2
can u explain it in depth please
thank u
i get that the horizontal line is 15
and its touching 1/2 of the circumference of each circle
but i stil dont get how this is formed 15-pi/2
can u explain it in depth please
thank u
The whole belt is made up of 2 horizontal parts (top and bottom) and 2 round half-circumference parts.
So:
15 = Top + bottom + 2 x half circle
Top = bottom (call this A)
15 = 2A + 2 x pi*d/2 (d=1)
15 = 2A + pi
15 - pi = 2A
A = (15 - pi)/2
So:
15 = Top + bottom + 2 x half circle
Top = bottom (call this A)
15 = 2A + 2 x pi*d/2 (d=1)
15 = 2A + pi
15 - pi = 2A
A = (15 - pi)/2
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- Senior | Next Rank: 100 Posts
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