Veritas Prep
An urn contains g green marbles and b blue marbles. If 3 green marbles and 5 blue marbles are added, and then one marble is selected at random from the urn, what is the probability that a blue marble will be drawn?
A. b/(b+g)
B. (b+5)/(g+3)
C. (b+5)/(b+g+8)
D. (b+5)/(b+g+3)
E. b/(b+g+5)
OA C
An urn contains g green marbles and b blue marbles. If 3 green marbles and 5 blue marbles are added, and then one...
This topic has expert replies
GMAT/MBA Expert
- Scott@TargetTestPrep
- GMAT Instructor
- Posts: 7251
- Joined: Sat Apr 25, 2015 10:56 am
- Location: Los Angeles, CA
- Thanked: 43 times
- Followed by:29 members
Solution:AAPL wrote: ↑Sat Mar 27, 2021 4:21 pmVeritas Prep
An urn contains g green marbles and b blue marbles. If 3 green marbles and 5 blue marbles are added, and then one marble is selected at random from the urn, what is the probability that a blue marble will be drawn?
A. b/(b+g)
B. (b+5)/(g+3)
C. (b+5)/(b+g+8)
D. (b+5)/(b+g+3)
E. b/(b+g+5)
OA C
After 3 green marbles and 5 blue marbles are added, the total number of marbles in the urn is g + b + 3 + 5 = b + g + 8, and the number of blue marbles in the urn is b + 5. Therefore, the probability that a blue marble will be drawn is (b + 5) / (b + g + 8).
Answer: C
Scott Woodbury-Stewart
Founder and CEO
[email protected]
See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews