An empty bucket being filled with paint at a constant rate takes 6 minutes to be filled to 7/10 of its capacity. How much more time will it take to fill the bucket to full capacity?
A. 7/18
B. 9/18
C. 2
D. 18/7
E. 18/5
OA D
Source: Manhattan Prep
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An empty bucket being filled with paint at a constant rate takes 6 minutes to be filled to 7/10 of its capacity. How
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BTGmoderatorDC
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We can create the proportion:BTGmoderatorDC wrote: ↑Wed Nov 03, 2021 6:42 amAn empty bucket being filled with paint at a constant rate takes 6 minutes to be filled to 7/10 of its capacity. How much more time will it take to fill the bucket to full capacity?
A. 7/18
B. 9/18
C. 2
D. 18/7
E. 18/5
OA D
Source: Manhattan Prep
6/(7/10) = n/(3/10)
60/7 = 10n/3
180 = 70n
180/70 = n
18/7 = n
Answer: D
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Suppose, capacity \(= 70 .\)BTGmoderatorDC wrote: ↑Wed Nov 03, 2021 6:42 amAn empty bucket being filled with paint at a constant rate takes 6 minutes to be filled to 7/10 of its capacity. How much more time will it take to fill the bucket to full capacity?
A. 7/18
B. 9/18
C. 2
D. 18/7
E. 18/5
OA D
Source: Manhattan Prep
So, to fill \(\dfrac{7}{10}\) of \(70\) i.e. \(49,\) it took \(6\) minutes.
Hence, to fill \(70\) it will take \(= 10\ast \dfrac{6}{7} = \dfrac{60}{7}\) minutes.
So, additional time \(= \dfrac{60}{7} - 6 = \dfrac{18}{7} \Longrightarrow \) D
