Alan and Peter are cycling at different constant rates on a straight track. If Alan is now 3 miles ahead of Peter, how many minutes from now will Peter be 1 mile ahead of Alan?

(1) One hour ago, Alan was 7 miles ahead of Peter.

(2) Alan is cycling at 14 miles per hour and Peter is cycling at 18 miles per hour.

OA is D

But i think OA should be B because in S(1) you can't find the speed of Alan. For Peter, i can get the speed of 4 mph as he covered 4 miles in 1 hr and now he is 3 miles behind Alan, but how to get Alan's speed.

Solve 700-Level Algebra Qs In 90 Secs!

Master 700-level Inequalities and Absolute Value Questions

Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease.

**
**

Alan is NOW 3 miles ahead of Peter

So, in one hour, the GAP between Alan and Peter decreased by 4 miles

Another way to put it: Peter's speed is 4 mph greater than Alan's speed.

Another way to put it: in one hour, Peter traveled 4 miles more than Alan

So, in ONE HOUR FROM NOW, Peter will travel another 4 miles more than Alan. This means the Peter will not only close the 3-mile gap BUT ALSO travel 1 mile further than Alan travels.

So, the answer to the target question is in 60 MINUTES, Peter will be 1 mile ahead of Alan

Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Another way to put it: Peter's speed is 4 mph greater than Alan's speed.

Another way to put it: in one hour, Peter travels 4 miles more than Alan

At this point, we can apply the same logic we applied to statement 1 to conclude that statement 2 is SUFFICIENT

Answer: D

Cheers,

Brent

$$?\,\,\,:\,\,\,\min \,\,{\rm{for}}\,\,4\,\,{\rm{miles - }}\underline {{\rm{gaining}}} \,\,\,{\rm{Peter}}/{\rm{Alan}}\,\,$$

$$\left( 1 \right)\,\,{\text{RelativeSpee}}{{\text{d}}_{{\text{Peter/Alan}}}}\,\,\, = \,\,\,\,\,\frac{{4\,\,{\text{miles}}}}{{\boxed{1\,\,{\text{hour}}}}}\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,? = \boxed{1\,{\text{h}}}\,\,\left( { = 60\min } \right)\,\,\,\,\,\, \Rightarrow \,\,\,\,\,{\text{SUFF}}.$$

$$\left( 2 \right)\,{\text{RelativeSpee}}{{\text{d}}_{{\text{Peter/Alan}}}}\,\,\,\, = \,\,\,\,\frac{{4\,\,{\text{miles}}}}{{\boxed{1\,\,{\text{hour}}}}}\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,? = \boxed{1\,{\text{h}}}\,\,\left( { = 60\min } \right)\,\,\,\,\,\, \Rightarrow \,\,\,\,\,{\text{SUFF}}.$$

This solution follows the notations and rationale taught in the GMATH method.

Regards,

Fabio.

## Alan and Peter are cycling at different constant rates on a

##### This topic has expert replies

### GMAT/MBA Expert

- [email protected]
- GMAT Instructor
**Posts:**16201**Joined:**Mon Dec 08, 2008 6:26 pm**Location:**Vancouver, BC**Thanked**: 5254 times**Followed by:**1268 members**GMAT Score:**770

## Timer

00:00

## Your Answer

**A**

**B**

**C**

**D**

**E**

## Global Stats

vinni.k wrote:Alan and Peter are cycling at different constant rates on a straight track. If Alan is now 3 miles ahead of Peter, how many minutes from now will Peter be 1 mile ahead of Alan?

(1) One hour ago, Alan was 7 miles ahead of Peter.

(2) Alan is cycling at 14 miles per hour and Peter is cycling at 18 miles per hour.

**Given: Alan is NOW 3 miles ahead of Peter**

**Target question:**

**How many minutes from now will Peter be 1 mile ahead of Alan?**

**Statement 1: ONE HOUR AGO, Alan was 7 miles ahead of Peter.**

Alan is NOW 3 miles ahead of Peter

So, in one hour, the GAP between Alan and Peter decreased by 4 miles

Another way to put it: Peter's speed is 4 mph greater than Alan's speed.

Another way to put it: in one hour, Peter traveled 4 miles more than Alan

So, in ONE HOUR FROM NOW, Peter will travel another 4 miles more than Alan. This means the Peter will not only close the 3-mile gap BUT ALSO travel 1 mile further than Alan travels.

So, the answer to the target question is in 60 MINUTES, Peter will be 1 mile ahead of Alan

Since we can answer the target question with certainty, statement 1 is SUFFICIENT

**Statement 2: Alan is cycling at 14 miles per hour and Peter is cycling at 18 miles per hour.**

Another way to put it: Peter's speed is 4 mph greater than Alan's speed.

Another way to put it: in one hour, Peter travels 4 miles more than Alan

At this point, we can apply the same logic we applied to statement 1 to conclude that statement 2 is SUFFICIENT

Answer: D

Cheers,

Brent

- [email protected]
- GMAT Instructor
**Posts:**1449**Joined:**Sat Oct 09, 2010 2:16 pm**Thanked**: 59 times**Followed by:**33 members

## Timer

00:00

## Your Answer

**A**

**B**

**C**

**D**

**E**

## Global Stats

Excellent opportunity for the relative velocity (speed) technique!vinni.k wrote:Alan and Peter are cycling at different constant rates on a straight track. If Alan is now 3 miles ahead of Peter, how many minutes from now will Peter be 1 mile ahead of Alan?

(1) One hour ago, Alan was 7 miles ahead of Peter.

(2) Alan is cycling at 14 miles per hour and Peter is cycling at 18 miles per hour.

$$?\,\,\,:\,\,\,\min \,\,{\rm{for}}\,\,4\,\,{\rm{miles - }}\underline {{\rm{gaining}}} \,\,\,{\rm{Peter}}/{\rm{Alan}}\,\,$$

$$\left( 1 \right)\,\,{\text{RelativeSpee}}{{\text{d}}_{{\text{Peter/Alan}}}}\,\,\, = \,\,\,\,\,\frac{{4\,\,{\text{miles}}}}{{\boxed{1\,\,{\text{hour}}}}}\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,? = \boxed{1\,{\text{h}}}\,\,\left( { = 60\min } \right)\,\,\,\,\,\, \Rightarrow \,\,\,\,\,{\text{SUFF}}.$$

$$\left( 2 \right)\,{\text{RelativeSpee}}{{\text{d}}_{{\text{Peter/Alan}}}}\,\,\,\, = \,\,\,\,\frac{{4\,\,{\text{miles}}}}{{\boxed{1\,\,{\text{hour}}}}}\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,? = \boxed{1\,{\text{h}}}\,\,\left( { = 60\min } \right)\,\,\,\,\,\, \Rightarrow \,\,\,\,\,{\text{SUFF}}.$$

This solution follows the notations and rationale taught in the GMATH method.

Regards,

Fabio.

Fabio Skilnik :: GMATH method creator ( Math for the GMAT)

English-speakers :: https://www.gmath.net

Portuguese-speakers :: https://www.gmath.com.br

English-speakers :: https://www.gmath.net

Portuguese-speakers :: https://www.gmath.com.br