Q9:How many years did Dr. Jones live?
(1) If Dr. Jones had become a doctor 10 years earlier than he did, he would have been a
doctor for exactly 2/3 of his life.
(2) If Dr. Jones had become a doctor 10 years later than he did, he would have been a doctor
for exactly 1/3 of his life.
OA: C
How????
Age?
This topic has expert replies
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- Master | Next Rank: 500 Posts
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..even i had arrived at that equation..but when you go ahead and solve it...you get 2D = T.
i think the answer is wrong>>>>
i think the answer is wrong>>>>
anandr84 wrote:D= no of years jones was a doc
T= total number of years he lived
1> D+10 = (2/3)T
INSUFFICIENT
2> D-10 = (1/3)T
INSUFFICIENT
1 & 2> Solving the simultaenuous equations we can get T
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- Junior | Next Rank: 30 Posts
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Subtract Eq 2 from eq 1,u'll get T = 60brick2009 wrote: ..even i had arrived at that equation..but when you go ahead and solve it...you get 2D = T.
i think the answer is wrong>>>>
anandr84 wrote:D= no of years jones was a doc
T= total number of years he lived
1> D+10 = (2/3)T
INSUFFICIENT
2> D-10 = (1/3)T
INSUFFICIENT
1 & 2> Solving the simultaenuous equations we can get T
-
- Master | Next Rank: 500 Posts
- Posts: 171
- Joined: Mon Jun 01, 2009 8:59 pm
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awwww.. true...
this is just great..weeks before the exam.. i forget the fundamentals..
this is just great..weeks before the exam.. i forget the fundamentals..
jaspreet_takhar wrote:Subtract Eq 2 from eq 1,u'll get T = 60brick2009 wrote: ..even i had arrived at that equation..but when you go ahead and solve it...you get 2D = T.
i think the answer is wrong>>>>
anandr84 wrote:D= no of years jones was a doc
T= total number of years he lived
1> D+10 = (2/3)T
INSUFFICIENT
2> D-10 = (1/3)T
INSUFFICIENT
1 & 2> Solving the simultaenuous equations we can get T
- grockit_jake
- GMAT Instructor
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yes, no need to plug in and solve on data sufficiency questions.
If there are 2 linear eqs and 2 unknowns (that are not identical multiples of each other) then you have a unique solution.
If there are 2 linear eqs and 2 unknowns (that are not identical multiples of each other) then you have a unique solution.