Adam, Bill, and Chris simultaneously start from City $A$ to City $B.$ Adam reaches City $B$ first, then turns back

Adam, Bill, and Chris simultaneously start from City $A$ to City $B.$ Adam reaches City $B$ first, then turns back and meets Bill at a distance of $9$ miles from City $B.$ When Bill reaches City $B,$ he too turns back and meets Chris at a distance of $7$ miles from City $B.$ If three times the speed of Adam is equal to five times Chris' speed, what could be the distance between the City $A$ and City $B?$

A. $40$ miles
B. $35$ miles
C. $63$ miles
D. $90$ miles
E. $120$ miles

The OA is C

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