Absolute Confusion!!!

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Absolute Confusion!!!

by vittalgmat » Tue Dec 15, 2009 4:45 pm
Hi,
I would like the experts to weigh in on this. (Ron, Ian, Stuart, Stacey??)
I will ask my question first.
What method is applicable to what class of problems?

As I understand, there are two ways to algebraically solve absolute equations (apart from the conceptual distance numberline method). The following are the two ways I found.

Method 1) Whenever u see problem of the type
Is |x| < 1 ?
(1) |x + 1| = 2|x - 1|

Solving the two cases a) (x +1 ) = 2(x-1) and
b) (x +1) = - 2(x -1)
are sufficient.
Ref: see Ron Purewal's explanation here:
https://www.manhattangmat.com/forums/abs ... t3648.html


Method 2) For solving problems of the type, we need to use a critical point approach

If y = /x + 7/ + /2 - x/, is y = 9?
(1) x < 2
(2) x > -7
(Ref: see the MGMAT Tutorial on Absolute values Slide 61
https://www.manhattangmat.com/tutorials/ ... -value.cfm )


The critical point approach is illustrated in the same tutorial. This link below also explains the critical point approach but as Ron mentioned, critical point approach is a overkill for that problem in the link below. It could have been solved by Method 1.

https://www.beatthegmat.com/tricky-inequ ... 22180.html

Thank you very much

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by sanju09 » Tue Dec 15, 2009 9:59 pm
Hope this link helps...

https://www.scribd.com/doc/7058655/Math- ... Inequality



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by vittalgmat » Tue Dec 15, 2009 10:06 pm
Sanju,
This is the same as the one mentioned in my original post!!!
https://www.manhattangmat.com/tutorials/ ... -value.cfm

Thanks

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by sanju09 » Tue Dec 15, 2009 10:24 pm
vittalgmat wrote:Sanju,
This is the same as the one mentioned in my original post!!!
https://www.manhattangmat.com/tutorials/ ... -value.cfm

Thanks
so what's the real hitch man? :?
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by vittalgmat » Tue Dec 15, 2009 10:36 pm
not sufficient.
I want to know how to figure out what to use when?
So whenever I see a problem of type | something | = | something else| then use method 1
ELSE I use method 2 ?

Is this a safe conclusion ?

thanks

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by sanju09 » Tue Dec 15, 2009 10:57 pm
I am sorry vittal as I haven't seen either of it so curiously, so I will try to explain my point on the particular problems later on; but for now, a quick tip from my experience, "ALGEBRA is the final resort to crack all LOGICS in QUICK time", other approaches are too welcome on "first come (to hit brain) first serve basis" only if that works for you in a given situation. Take care and greet me as this one is my 700th post on this forum; which I have noted just now, honestly... :D
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by vittalgmat » Tue Dec 15, 2009 11:05 pm
Thanks Sanju for all your efforts
I have PMed Ron Purewal. Hopefull he will answer soon.

Btw u still have 60 more post to go before equating the # of posts with Gmat score.

thanks

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by sanju09 » Tue Dec 15, 2009 11:19 pm
Thank you so much and congratulations vittal for still being "Hopefull" here, since all of us are only "Hopeful" here; but you are a bit mo+re than us.......just kidding...sorry....have fun2
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by vittalgmat » Wed Dec 16, 2009 9:51 am
Sanju,
That is called "unintended typo" or "printer's devil". But the typo probably reflected my true inner nature ;-)

have a nice day

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by sanju09 » Wed Dec 16, 2009 11:30 pm
vittalgmat wrote:Sanju,
That is called "unintended typo" or "printer's devil". But the typo probably reflected my true inner nature ;-)

have a nice day
so nice of you vittal, thank you
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by lunarpower » Fri Dec 18, 2009 10:41 pm
vittalgmat wrote:Method 2) For solving problems of the type, we need to use a critical point approach

If y = /x + 7/ + /2 - x/, is y = 9?
(1) x < 2
(2) x > -7
(Ref: see the MGMAT Tutorial on Absolute values Slide 61
https://www.manhattangmat.com/tutorials/ ... -value.cfm )
yeah, some sort of "critical point" approach is going to be the best way to hack away at a problem like that one. no doubt.

since these are INEQUALITIES, though, you can also use the backup method of TESTING EXTREMES.

i.e.
statement 1:
TEST EXTREMES
test x = 1.9 (i.e. very close to 2) --> y = |8.9| + |0.1| --> y = 9 YES
test x = -1000 (the other extreme) --> y = |-993| + |1002| --> y is not 9 NO
insufficient.

statement 2:
TEST EXTREMES
test x = -6.9 (i.e. very close to -7) --> y = |0.1| + |8.9| --> y = 9 YES
test x = 1000 (the other extreme) --> y = |1007| + |-998| --> y is not 9 NO
insufficient.

together:
TEST EXTREMES
test x = -6.9 (i.e. very close to -7) --> y = |0.1| + |8.9| --> y = 9 YES
test x = 1.9 (i.e. very close to 2) --> y = |8.9| + |0.1| --> y = 9 YES
test other values in the middle, if you're still skeptical
you'll get all YES's
SUFFICIENT

(c)
Ron has been teaching various standardized tests for 20 years.

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