In which quadrant of the coordinate plane does the point (x,y) lie?
(1) |xy| + x|y| + |x|y + xy > 0
(2) -x < -y < |y|
Abs: coordinate plane of (x,y)
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Statement 1: |xy| + x|y| + |x|y + xy > 0euro wrote:In which quadrant of the coordinate plane does the point (x,y) lie?
(1) |xy| + x|y| + |x|y + xy > 0
(2) -x < -y < |y|
As |xy| + x|y| + |x|y + xy > 0
-> |x||y| + x|y| + |x|y + xy > 0
-> |y|*(|x| +x) + y*(|x| + x) > 0
-> (|x| + x)*(|y| + y) > 0
This means (|x| + x) and (|y| + y) are of same sign and none of them is equal to zero.
Now, the values of (|x| + x) can never be negative because,
- (1) |x| + x = x + x = 2x , for x positive
(2) |x| + x = -x + x = 0 , for x negative
Therefore, (|x| + x) and (|y| + y) both are positive as none of them can be zero. This also means that x and y are positive too. So, the point (x, y lies in the first quadrant.
Sufficient.
Statement 2: -x < -y < |y|
Observe that,
- (1) For y positive, |y| = y. Thus, |y| > -y
(2) For y negative, |y| = -y. Thus, |y| is not greater than -y.
Now, -x < -y. This implies x > y. As y is positive, x must be positive. The point (x, y) lies in the first quadrant.
Sufficient.
The correct answer is D.
Rahul Lakhani
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Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
from (1)... xy| + x|y| + |x|y + xy > 0
Consider (x,y) present in all Quadrants..
when substituted in the inequality ,
(+x,+y) ==> ++++>0 -Yes
(+,-)==>+ + - - = 0 -No
(-,-)==>+ - - + = 0 -No
(-,+)==> + - + - = 0 -No
Only one option satisfies the condition given in (1) i.e when (x,y) in Q1.
from (2) ,
same as explained by Rahul..
Hence (D)
Consider (x,y) present in all Quadrants..
when substituted in the inequality ,
(+x,+y) ==> ++++>0 -Yes
(+,-)==>+ + - - = 0 -No
(-,-)==>+ - - + = 0 -No
(-,+)==> + - + - = 0 -No
Only one option satisfies the condition given in (1) i.e when (x,y) in Q1.
from (2) ,
same as explained by Rahul..
Hence (D)