Abs: coordinate plane of (x,y)

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Abs: coordinate plane of (x,y)

by euro » Tue Nov 02, 2010 1:36 am
In which quadrant of the coordinate plane does the point (x,y) lie?

(1) |xy| + x|y| + |x|y + xy > 0

(2) -x < -y < |y|

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by Rahul@gurome » Tue Nov 02, 2010 2:25 am
euro wrote:In which quadrant of the coordinate plane does the point (x,y) lie?

(1) |xy| + x|y| + |x|y + xy > 0

(2) -x < -y < |y|
Statement 1: |xy| + x|y| + |x|y + xy > 0
As |xy| + x|y| + |x|y + xy > 0
-> |x||y| + x|y| + |x|y + xy > 0
-> |y|*(|x| +x) + y*(|x| + x) > 0
-> (|x| + x)*(|y| + y) > 0

This means (|x| + x) and (|y| + y) are of same sign and none of them is equal to zero.
Now, the values of (|x| + x) can never be negative because,
  • (1) |x| + x = x + x = 2x , for x positive
    (2) |x| + x = -x + x = 0 , for x negative
Same for (|y| + y).
Therefore, (|x| + x) and (|y| + y) both are positive as none of them can be zero. This also means that x and y are positive too. So, the point (x, y lies in the first quadrant.

Sufficient.

Statement 2: -x < -y < |y|
Observe that,
  • (1) For y positive, |y| = y. Thus, |y| > -y
    (2) For y negative, |y| = -y. Thus, |y| is not greater than -y.
Therefore, for |y| to greater than -y, y must be positive.

Now, -x < -y. This implies x > y. As y is positive, x must be positive. The point (x, y) lies in the first quadrant.

Sufficient.

The correct answer is D.
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by ymach3 » Fri Nov 19, 2010 1:43 am
from (1)... xy| + x|y| + |x|y + xy > 0

Consider (x,y) present in all Quadrants..

when substituted in the inequality ,

(+x,+y) ==> ++++>0 -Yes
(+,-)==>+ + - - = 0 -No
(-,-)==>+ - - + = 0 -No
(-,+)==> + - + - = 0 -No

Only one option satisfies the condition given in (1) i.e when (x,y) in Q1.

from (2) ,

same as explained by Rahul..

Hence (D)