A shipment of 70 items is to be divided into three lots. How many pieces are in the largest of the three lots ?
1. The number of items in the largest lot is equal to the sum of number of items in the other two lots.
2. The smallest lot contains 10 items.
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A shipment of 70
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madhur_ahuja
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cubicle_bound_misfit
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IMO it is A.
as stmt 1 can only be satisfied when
largest lot has 35 items.
any other way it is not possible.
Stmt 2. smallest one having 10 can lead to multiple situation
i.e 10+20+40
or 10+15+45 etc hence Insuff
HTH
as stmt 1 can only be satisfied when
largest lot has 35 items.
any other way it is not possible.
Stmt 2. smallest one having 10 can lead to multiple situation
i.e 10+20+40
or 10+15+45 etc hence Insuff
HTH
Cubicle Bound Misfit
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gmat_dest
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(A) is sufficient.
70 = Largest + (sum of Other 2 numbers)
its given that largest = sum of other 2 numbers
Hence, you can find out largest.
(B) gives only smallest. So, we can't find out largest.
70 = Largest + (sum of Other 2 numbers)
its given that largest = sum of other 2 numbers
Hence, you can find out largest.
(B) gives only smallest. So, we can't find out largest.
