A school supply store sells only one kind of desk and one kind of chair, at a uniform cost per desk or per chair. If the total cost of 3 desks and 1 chair is twice that of 1 desk and 3 chairs, then the total cost of 4 desks and 1 chair is how many times that of 1 desk and 4 chairs?
A. 5
B. 3
C. 8/3
D. 5/2
E. 7/3
OA E
Source: Official Guide
A school supply store sells only one kind of desk and one
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Hi All,
We're told that a school supply store sells only one kind of desk and one kind of chair, at a uniform cost per desk or per chair. The total cost of 3 desks and 1 chair is TWICE that of 1 desk and 3 chairs. We're asked - the total cost of 4 desks and 1 chair is how many times that of 1 desk and 4 chairs. This question is ultimately about ratios - and you have to do a little Algebra to work through it.
The information that we're given can be translated into the following equation:
3D + C = 2(D + 3C)
We can then do a couple Algebra steps to simplify this equation:
3D + C = 2D + 6C
D = 5C
We now know that 1 desk is the same price as 5 chairs. With this information, we can substitute in to the given question:
Cost of 4 desks and 1 chair = 4D + 1C = 4(5C) + 1C = 21C
Cost of 1 desk and 4 chairs = 1D + 4C = 1(5C) + 4C = 9C
21C/9C = 7/3
Final Answer: E
GMAT assassins aren't born, they're made,
Rich
We're told that a school supply store sells only one kind of desk and one kind of chair, at a uniform cost per desk or per chair. The total cost of 3 desks and 1 chair is TWICE that of 1 desk and 3 chairs. We're asked - the total cost of 4 desks and 1 chair is how many times that of 1 desk and 4 chairs. This question is ultimately about ratios - and you have to do a little Algebra to work through it.
The information that we're given can be translated into the following equation:
3D + C = 2(D + 3C)
We can then do a couple Algebra steps to simplify this equation:
3D + C = 2D + 6C
D = 5C
We now know that 1 desk is the same price as 5 chairs. With this information, we can substitute in to the given question:
Cost of 4 desks and 1 chair = 4D + 1C = 4(5C) + 1C = 21C
Cost of 1 desk and 4 chairs = 1D + 4C = 1(5C) + 4C = 9C
21C/9C = 7/3
Final Answer: E
GMAT assassins aren't born, they're made,
Rich
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Let's let D = the cost of a desk and C = the cost of a chair. We can create the equation:BTGmoderatorDC wrote:A school supply store sells only one kind of desk and one kind of chair, at a uniform cost per desk or per chair. If the total cost of 3 desks and 1 chair is twice that of 1 desk and 3 chairs, then the total cost of 4 desks and 1 chair is how many times that of 1 desk and 4 chairs?
A. 5
B. 3
C. 8/3
D. 5/2
E. 7/3
OA E
Source: Official Guide
3D + C = 2(D + 3C)
3D + C = 2D + 6C
D = 5C
Let's let K = the number of times greater that one desk and 4 chairs costs, compared to the cost of 4 desks and 1 chair. So, we have:
4D + C = K(D + 4C) ?
Substituting 5C for D, we have:
20C + C = K(5C + 4C) ?
21C= K(9C) ?
K = 21C/9C = 7/3
Answer: E
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