A mountain resort will hold its annual one-day snowboarding competition if it snows on either Saturday or Sunday, but if

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A mountain resort will hold its annual one-day snowboarding competition if it snows on either Saturday or Sunday, but if it does not snow at all it will not hold the event. If there is a 70% chance that it snows on any given day at the resort, what is the probability that the event will be held?

A. 70%
B. 80%
C. 81%
D. 90%
E. 91%


OA E

Source: Veritas Prep

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BTGmoderatorDC wrote:
Tue Jun 02, 2020 7:40 pm
A mountain resort will hold its annual one-day snowboarding competition if it snows on either Saturday or Sunday, but if it does not snow at all it will not hold the event. If there is a 70% chance that it snows on any given day at the resort, what is the probability that the event will be held?

A. 70%
B. 80%
C. 81%
D. 90%
E. 91%

OA E

Source: Veritas Prep
Given that there is a 70% chance that it snows on any given day at the resort, there is a 100% – 70% = 30% chance that it does not snow on any given day at the resort.

The event will not be held if there is no snow on either day.

So, the probability that the event will not be held = 30%*30% = 9%

So, the probability that the event will be held = 100% – 9% = 91%

The correct answer: E

Hope this helps!

-Jay
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BTGmoderatorDC wrote:
Tue Jun 02, 2020 7:40 pm
A mountain resort will hold its annual one-day snowboarding competition if it snows on either Saturday or Sunday, but if it does not snow at all it will not hold the event. If there is a 70% chance that it snows on any given day at the resort, what is the probability that the event will be held?

A. 70%
B. 80%
C. 81%
D. 90%
E. 91%


OA E

Solution:

We see that they will NOT hold the event only if it does not snow on Saturday and it does not snow on Sunday. Since the probability is 0.7 that it will snow on any given day, we see that the probability that it will NOT snow on any given day is (1 - 0.7) = 0.3. We can use the formula:

P(hold the event) = 1 - P(not hold the event)

P(not hold the event) = 0.3 x 0.3 = 0.09.

So P(hold the event) = 1 - 0.09 = 0.91 = 91%.

Answer: E

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