A mother and father have seven children, and the family receives an invitation with four tickets to the circus. If the family decides to randomly select the four members who get to attend the circus, but determine that the chosen group must include at least one of the mother and father, how many different groups are possible to send to the circus?
A. 70
B. 84
C. 91
D. 108
E. 126
OA C
Source: Veritas Prep
A mother and father have seven children, and the family receives an invitation with four tickets to the circus. If the
This topic has expert replies
-
- Moderator
- Posts: 7187
- Joined: Thu Sep 07, 2017 4:43 pm
- Followed by:23 members
Timer
00:00
Your Answer
A
B
C
D
E
Global Stats
We have two ways to selectBTGmoderatorDC wrote: ↑Mon Aug 23, 2021 7:01 pmA mother and father have seven children, and the family receives an invitation with four tickets to the circus. If the family decides to randomly select the four members who get to attend the circus, but determine that the chosen group must include at least one of the mother and father, how many different groups are possible to send to the circus?
A. 70
B. 84
C. 91
D. 108
E. 126
OA C
Source: Veritas Prep
1) Mother or father along with \(3\) of their children.
\(2C1\ast 7C3=2 \times 35=70\)
2) Both mother and father along with \(2\) of their children.
\(2C2\ast 7C2= 1\times 21\)
So, \(70+21=91 \Longrightarrow\) C