A lecture course consists of 595 students. The students are to be divided into discussion sections, each with an equal number of students. Which of the following cannot be the number of students in a discussion section.
a) 17
b) 35
c) 45
d) 85
e) 119
Answer: C
Source: Veritas Prep
A lecture course consists of 595 students. The students
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In order to have an EQUAL number of students in each section, the number of students per section MUST BE A FACTOR of 595BTGModeratorVI wrote: ↑Wed Jul 29, 2020 2:43 pmA lecture course consists of 595 students. The students are to be divided into discussion sections, each with an equal number of students. Which of the following cannot be the number of students in a discussion section.
a) 17
b) 35
c) 45
d) 85
e) 119
Answer: C
Source: Veritas Prep
Let's do some prime factorization
595 = (5)(7)(17)
From the prime factorization, we can see that answer choice A, B, D and E are all factors of 595
Answer: C
Cheers,
Brent
We are being asked to find that 595 is not divisible by which number among the given options.
595 = 5 * 7 * 17
17: Prime factor of 595
35: 5 * 7
85: 5 * 17
119: 7*17
45: Cannot be formed by the prime factors of 595.
Answer C
Thanks,
Sayon
595 = 5 * 7 * 17
17: Prime factor of 595
35: 5 * 7
85: 5 * 17
119: 7*17
45: Cannot be formed by the prime factors of 595.
Answer C
Thanks,
Sayon