A lecture course consists of 595 students. The students

This topic has expert replies
Legendary Member
Posts: 1223
Joined: 15 Feb 2020
Followed by:1 members

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

A lecture course consists of 595 students. The students are to be divided into discussion sections, each with an equal number of students. Which of the following cannot be the number of students in a discussion section.

a) 17
b) 35
c) 45
d) 85
e) 119


Answer: C
Source: Veritas Prep

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 15948
Joined: 08 Dec 2008
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1267 members
GMAT Score:770
BTGModeratorVI wrote:
Wed Jul 29, 2020 2:43 pm
A lecture course consists of 595 students. The students are to be divided into discussion sections, each with an equal number of students. Which of the following cannot be the number of students in a discussion section.

a) 17
b) 35
c) 45
d) 85
e) 119


Answer: C
Source: Veritas Prep
In order to have an EQUAL number of students in each section, the number of students per section MUST BE A FACTOR of 595

Let's do some prime factorization
595 = (5)(7)(17)
From the prime factorization, we can see that answer choice A, B, D and E are all factors of 595

Answer: C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image

Junior | Next Rank: 30 Posts
Posts: 13
Joined: 01 Aug 2020
We are being asked to find that 595 is not divisible by which number among the given options.

595 = 5 * 7 * 17

17: Prime factor of 595
35: 5 * 7
85: 5 * 17
119: 7*17

45: Cannot be formed by the prime factors of 595.

Answer C


Thanks,
Sayon