Problem Solving

A day is divided into 10 new-hours, each new-hour is divided into 100 new-minutes and each new-minute is divided into 100 new-seconds. In terms of time elapsed, what is the ratio of a new-second to an ordinary second?

A. 3/5
B. 108/125
C. 1
D. 125/108
E. 5/3

The OA is B.

I get the solution of the following way,

Number of seconds in an ordinary day = 24*60*60

Number of seconds in the new day = 10*100*100

Clearly, new day has more number of seconds than the ordinary day.

So, new seconds must take less time when compared to the ordinary one.

So, the ration of new seconds to old seconds... (24*60*60) / (10*100*100) = 108/125.

Has anyone another strategic approach to solve this PS question? Regards!

Time in seconds = $$hours\cdot\min utes\cdot\sec onds$$
$$New\ \sec ond=\frac{1}{10\cdot100\cdot100}$$
$$old\sec ond=\frac{1}{24\cdot60\cdot60}$$
$$Ratio\ of\ new\ \sec ond\ to\ ordinary\ \sec ond,\ we\ have,\ \frac{\left(new\ \sec ond\right)}{\left(old\ \sec ond\right)}=\frac{\left(24\cdot60\cdot60\right)}{\left(10\cdot100\cdot100\right)}$$
$$=\frac{108}{125}\ \ \left(option\ B\right)$$