A bag contains x blue chips and y red chips. If the probability of selecting a red chip at random is 3/7, then x/y =
A. 7/11
B. 3/4
C. 7/4
D. 4/3
E. 11/7
Answer: D
Source: Magoosh
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A bag contains x blue chips and y red chips. If the probability
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BTGModeratorVI
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We can quickly solve this question by testing values that satisfy the given informationBTGModeratorVI wrote: ↑Tue Feb 18, 2020 11:07 amA bag contains x blue chips and y red chips. If the probability of selecting a red chip at random is 3/7, then x/y =
A. 7/11
B. 3/4
C. 7/4
D. 4/3
E. 11/7
Answer: D
Source: Magoosh
GIVEN: The probability of selecting a red chip at random is 3/7
So, it COULD be the case that there are 3 red chips, and a TOTAL of 7 chips
If there are 7 chips and 3 are red, then the other 4 chips must be blue
In other words, y = 3 and x = 4
This means x/y = 4/3
Answer: D
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Scott@TargetTestPrep
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Based on the given information, we can create the equation:BTGModeratorVI wrote: ↑Tue Feb 18, 2020 11:07 amA bag contains x blue chips and y red chips. If the probability of selecting a red chip at random is 3/7, then x/y =
A. 7/11
B. 3/4
C. 7/4
D. 4/3
E. 11/7
Answer: D
Source: Magoosh
y/(x + y) = 3/7
3(x + y) = 7y
3x + 3y = 7y
3x = 4y
x/y = 4/3
Answer: D
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