A bag contains x blue chips and y red chips. If the probability of selecting a red chip at random is 3/7, then x/y =
A. 7/11
B. 3/4
C. 7/4
D. 4/3
E. 11/7
Answer: D
Source: Magoosh
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A bag contains x blue chips and y red chips. If the probability of selecting a red chip at random is 3/7, then x/y =
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BTGModeratorVI
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terminator12
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Probability of selecting red chip = \(\frac{y}{x+\ y}\) = \(\frac{3}{7}\)
Solving this, we get \(\frac{x}{y}\) = \(\frac{4}{3}\)
Solving this, we get \(\frac{x}{y}\) = \(\frac{4}{3}\)
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Brent@GMATPrepNow
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We can quickly solve this question by testing values that satisfy the given informationBTGModeratorVI wrote: ↑Wed Jul 29, 2020 2:42 pmA bag contains x blue chips and y red chips. If the probability of selecting a red chip at random is 3/7, then x/y =
A. 7/11
B. 3/4
C. 7/4
D. 4/3
E. 11/7
Answer: D
Source: Magoosh
GIVEN: The probability of selecting a red chip at random is 3/7
So, it COULD be the case that there are 3 red chips, and a TOTAL of 7 chips
If there are 7 chips and 3 are red, then the other 4 chips must be blue
In other words, y = 3 and x = 4
This means x/y = 4/3
Answer: D
Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
