if A^2=B
is the value of A between 0 and 1?
1. b is between 0 and 1
2. a>b
puzzled i rephrased this and it got even worse.
qa is b
800 d
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Ans can not be A, it is B
(A) 0<b<1 so A can be -1<A<1
so insufficient
(B) A>B and A^2 = B so we know that A is a real fraction since only in case of a real fraction the square is less than or equal to the original value, meaning that A is 0<A<1
E.g. A = 1/2 and B=1/4
A = 1/3 and B = 1/9
(A) 0<b<1 so A can be -1<A<1
so insufficient
(B) A>B and A^2 = B so we know that A is a real fraction since only in case of a real fraction the square is less than or equal to the original value, meaning that A is 0<A<1
E.g. A = 1/2 and B=1/4
A = 1/3 and B = 1/9