500 PS TEST25#14

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500 PS TEST25#14

by dunkin77 » Wed Apr 18, 2007 11:49 am
Hi,

The answer is C) but again, could not figure out.... Can anyone help?
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by Ramesh2007 » Wed Apr 18, 2007 4:08 pm
First day:
Mowed 1/3
remaining = 1-(1/3) = 2/3

second day:
mowed 1/2 of remaining 2/3 = 2/3 * 1/2 = 2/6 = 1/3
remaining = 2/3 - 1/3 = 1/3

thrid day:
mowed 3/4 of remaining 1/3 = 1/3 * 3/4 = 3/12 = 1/4

remaining = 1 - Total mowed = 1 - (1/3 + 1/3 + 1/4) = 1 - (11/12) = 1/12

ANSWER C.

Can somebody confirm this please.

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by jayhawk2001 » Wed Apr 18, 2007 8:19 pm
Ramesh2007 wrote: ANSWER C.

Can somebody confirm this please.
C is correct.

1 - [ 1/3 + 1/2*2/3 + 3/4*{ 1- (1/3 + 1/3)} ]
= 1/12

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by Cybermusings » Thu Apr 19, 2007 1:36 am
Easy

First day 1/3 done
Remainder = 1-(1/3)=2/3
2nd day 1/2 of 2/3 = 1/3
Remainder = (2/3) - (1/3) = 1/3
3rd day 3/4 of 1/3 = 1/4
Remainder = 1/3 - (1/4) = 1/12