Hi,
I could not find an answer for this question but I think the answer is B) -- Can anyone please tell me B) is correct?
15. A certain used-book dealer sells paperback books at 3 times dealer's cost and hardback books at 4 times dealer's cost. Last week the dealer sold a total of 120 books, each of which had cost the dealer $1. If the gross profit (sales revenue minus dealer's cost) on the sale of all of these books was $300, how many of the books sold were paperbacks?
(A) 40
(B) 60
(C) 75
(D) 90
(E) 100
500 ps test 22 test#15
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- jayhawk2001
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Thank you Jay for your response.
What I thought I did was...
3P + 4H = 300
P + H = 120
3P+4(120-p)=300
p=180???
I thought I got B) but now I can't remember how I got p=60.
Can you explain how come you add 120 to 300 ?
What I thought I did was...
3P + 4H = 300
P + H = 120
3P+4(120-p)=300
p=180???
I thought I got B) but now I can't remember how I got p=60.
Can you explain how come you add 120 to 300 ?
- jayhawk2001
- Community Manager
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- Joined: Sun Jan 28, 2007 3:51 pm
- Location: Silicon valley, California
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The question states that the difference between the revenusdunkin77 wrote:Thank you Jay for your response.
What I thought I did was...
3P + 4H = 300
P + H = 120
3P+4(120-p)=300
p=180???
I thought I got B) but now I can't remember how I got p=60.
Can you explain how come you add 120 to 300 ?
and the cost is 300. The cost is 120 * $1 = 120. Hence 120 + 300
is the total sale price.
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Suppose the dealer sold x paperback books and y hardback books.
x+y = 120 ---------- 1)
3x+4y-120 = 300 ------- 2)
Solving the 2 you'll get x = 60 books
x+y = 120 ---------- 1)
3x+4y-120 = 300 ------- 2)
Solving the 2 you'll get x = 60 books