Hi,
I thought the answer was D) by 50 - 2inc = 38 inc=6 therefore 50-6=44 but turned out the answer is E)...can anyone help?
An instructor scored a student’s test of 50 questions by subtracting 2 times the number of incorrect answers from the number of correct answers. If the student answered all of the questions and received a score of 38, how many questions did that student answer correctly?
(A) 19
(B) 38
(C) 41
(D) 44
(E) 46
500 ds
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- jayhawk2001
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Let c and i be the number of correct and incorrect questions resp.
We have 2 equations --
c - 2i = 38
c + i = 50
Solving for c, we get 46. Hence E
We have 2 equations --
c - 2i = 38
c + i = 50
Solving for c, we get 46. Hence E
- ajith
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The problem lies in the underlined part,dunkin77 wrote:Hi,
I thought the answer was D) by 50 - 2inc = 38 inc=6 therefore 50-6=44 but turned out the answer is E)...can anyone help?
The total marks = Number of Correct answers - 2* Incorrect answers
(no of correct answers is not 50 it is 50-inc)
now,
50-inc-2*inc=38
=> inc =4
that leaves 46 as the answer
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Let total number of incorrect answers be x. Thus the teacher substracted 2x from the number of correct answers (number of correct answers would obviously be equal to 50 - x)
50 - x - 2x = 38
12 = 3x
x = 4. Hence correct answers = 50-4 = 46
50 - x - 2x = 38
12 = 3x
x = 4. Hence correct answers = 50-4 = 46