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X grams

This topic has 1 expert reply and 0 member replies

X grams

Post Wed Sep 13, 2017 2:13 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    X grams of water were added to 80 grams of a strong solution of acid. If as a result, the concentration of acid in the solution became 1/Y times of the initial concentration, what was the concentration of acid in the original solution?


    (1) X = 80

    (2) Y = 2

    What is the best way to determine on which of the 2 statements are the correct answer?

    OA E

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    Post Fri Sep 15, 2017 1:10 am
    lheiannie07 wrote:
    X grams of water were added to 80 grams of a strong solution of acid. If as a result, the concentration of acid in the solution became 1/Y times of the initial concentration, what was the concentration of acid in the original solution?

    (1) X = 80
    (2) Y = 2

    What is the best way to determine on which of the 2 statements are the correct answer?

    OA E
    Say out of 80 grams, the original solution had p grams of acid, thus, the original concentration of acid = p/80.

    After the addition of x grams of water, the new concentration of acid = p/(80 + x)

    We are given that

    New concentration = 1/y * Original concentration

    => p/(80+x) = p/80y

    y = 80/(80+x); 'p' cancels

    The above equation suggests that even if we get the values of x and y, we cannot get the value of p/80, thus none of the statements are sufficient.

    The correct answer: E

    Hope this helps!

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    Thanked by: lheiannie07

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