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Atult718
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 Posted: Fri Jul 13, 2007 4:30 am Post subject: What is the simplest way to tacke this ques? |
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Hey guys,
How would you tackle this problem
5^21 x 4^11 = 2 x 10^n |
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gabriel
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| Posted: Fri Jul 13, 2007 5:49 am Post subject: Re: What is the simplest way to tacke this ques? |
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| Atult718 wrote: | Hey guys,
How would you tackle this problem
5^21 x 4^11 = 2 x 10^n |
remember (x*y)^n = x^n*y^n ...
so 10^n=(2*5)^n = 2^n*5^n ...
also 4^11 = (2^2)^11 = 2^22 ..
So ... we have 5^21*2^22= 2 * 2^n*5^n .. that is 5^21*2^21= 2^n*5^n .. comparing the power on both the sides of the equation we get n = 21 ... |
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Atult718
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| Posted: Fri Jul 13, 2007 7:06 am Post subject: |
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| thanks for the great explanation gabriel. |
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