if x<0 , then Sq.Root(-x*|x|) is
x or -x ??
Do we always take the square root of 4 as 2 on GMAT or -2 is also a correct choice !!!
This was in one of my PP tests
PP Test Prob
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- aim-wsc
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both -ve as well as +ve value.
you always take both values in GMAT
whats the problem btw?
you always take both values in GMAT
whats the problem btw?
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this was the prob.
and it had both the options x as well as -x
however, i came across in the OG that root of a no will always be positive...
so sq root(9) will be 3
and therefore i think, sq root of (-3*-3) will also be 3
and it had both the options x as well as -x
however, i came across in the OG that root of a no will always be positive...
so sq root(9) will be 3
and therefore i think, sq root of (-3*-3) will also be 3
- aim-wsc
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all right.
but be careful in DS questions they consider both cases in DS.
but be careful in DS questions they consider both cases in DS.
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Plzz ignore my previous reply.. dont know how to delete that...
See Square root of a no can be +ve or -ve
And Sqaure root of a -ve no is not possible, its undefined
So for this question
if x<0 , then Sq.Root(-x*|x|) is
assume x=-4
Sq.Root(-(-4)*|-4|) = Sq.Root (4*4) = Sq.Root (16 ) = +4 or -4
So the answer to this question is x and -x
See Square root of a no can be +ve or -ve
And Sqaure root of a -ve no is not possible, its undefined
So for this question
if x<0 , then Sq.Root(-x*|x|) is
assume x=-4
Sq.Root(-(-4)*|-4|) = Sq.Root (4*4) = Sq.Root (16 ) = +4 or -4
So the answer to this question is x and -x