[GMAT math practice question]
$$If\ \ x+2y\ne0,is\frac{x}{x+2y}<1?$$
1) 10|x|=|y|
2) x>0
If x+2y≠0, is x/x+2y<1?
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Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Since we have 2 variables (x and y) and 0 equations, C is most likely to be the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.
Conditions 1) & 2) together:
10|x|=|y|
=> y = ±10x
Case 1: y = 10x
x/(x+2y) = x/(x+20x) = x/21x = 1/21 < 1
Case 2: y = -10x
x/(x+2y) = x/(x-20x) = x/(-19)x = -(1/19) < 1
Both conditions together are sufficient.
Since this question is an inequality question (one of the key question areas), CMT (Common Mistake Type) 4(A) of the VA (Variable Approach) method tells us that we should also check answers A and B.
Condition 1):
10|x|=|y|
=> y = ±10x
Case 1: y = 10x
x/(x+2y) = x/(x+20x) = x/21x = 1/21 < 1
Case 2: y = -10x
x/(x+2y) = x/(x-20x) = x/(-19)x = -(1/19) < 1
Thus, condition 1) only is sufficient.
Condition 2):
Since it gives us no information about y, condition 2) is not sufficient.
Therefore, A is the answer.
Answer: A
Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Since we have 2 variables (x and y) and 0 equations, C is most likely to be the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.
Conditions 1) & 2) together:
10|x|=|y|
=> y = ±10x
Case 1: y = 10x
x/(x+2y) = x/(x+20x) = x/21x = 1/21 < 1
Case 2: y = -10x
x/(x+2y) = x/(x-20x) = x/(-19)x = -(1/19) < 1
Both conditions together are sufficient.
Since this question is an inequality question (one of the key question areas), CMT (Common Mistake Type) 4(A) of the VA (Variable Approach) method tells us that we should also check answers A and B.
Condition 1):
10|x|=|y|
=> y = ±10x
Case 1: y = 10x
x/(x+2y) = x/(x+20x) = x/21x = 1/21 < 1
Case 2: y = -10x
x/(x+2y) = x/(x-20x) = x/(-19)x = -(1/19) < 1
Thus, condition 1) only is sufficient.
Condition 2):
Since it gives us no information about y, condition 2) is not sufficient.
Therefore, A is the answer.
Answer: A
Math Revolution
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Score an excellent Q49-51 just like 70% of our students.
[Free] Full on-demand course (7 days) - 100 hours of video lessons, 490 lesson topics, and 2,000 questions.
[Course] Starting $79 for on-demand and $60 for tutoring per hour and $390 only for Live Online.
Email to : [email protected]