If x and y are positive numbers, is

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If x and y are positive numbers, is

by jjjinapinch » Tue Aug 01, 2017 9:56 am

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If x and y are positive numbers, is (x+1)/(y+1) > x/y?

(1) x > 1
(2) x < y

Official Guide question
Answer: B

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by Brent@GMATPrepNow » Tue Aug 01, 2017 10:17 am

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jjjinapinch wrote:If x and y are positive numbers, is (x+1)/(y+1) > x/y?

(1) x > 1
(2) x < y

Official Guide question
Answer: B
Target question: Is (x + 1)/(y + 1) > x/y ?

Given: x and y are positive numbers
This is a great candidate for rephrasing the target question
We have the inequality: (x + 1)/(y + 1) > x/y
Since y is positive, we can multiply both sides of the inequality by y
Likewise, since y is positive, we know that y+1 is positive, which means we can multiply both sides of the inequality by (y+1)
When perform both of these multiplications we get: (x + 1)(y) > (x)(y + 1)
Expand to get: xy + y > xy + x
Subtract xy from both sides to get: y > x
So, we can now ask...
REPHRASED target question: Is y > x ?

Statement 1: x > 1
There's no information about y, so there's no way to determine whether or not y > x
Since we cannot answer the REPHRASED target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: x < y
Perfect!!!
Since we can answer the REPHRASED target question with certainty, statement 2 is SUFFICIENT

Answer: B

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by Jeff@TargetTestPrep » Wed Aug 09, 2017 11:13 am

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jjjinapinch wrote:If x and y are positive numbers, is (x+1)/(y+1) > x/y?

(1) x > 1
(2) x < y

Official Guide question
Answer: B
We can simplify the given question:

Is (x+1)/(y+1) > x/y ?

Is y(x + 1) > x(y + 1) ?

Is yx + y > xy + x ?

Is y > x ?

Statement One Alone:

x > 1

Since we know nothing about y, statement one alone is not sufficient to answer the question.

Statement Two Alone:

x < y

Since we see that x is less than y, we have answered the question.

Answer: B

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by [email protected] » Wed Apr 04, 2018 7:24 pm

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Hi All,

We're told that X and Y are POSITIVE numbers. We're asked if (X+1)/(Y+1) is greater than X/Y. This is a YES/NO question can be solved with a mix of TESTing VALUES and a rarer Number Property rule.

1) X > 1

IF....
X = 2 and Y=1, then we have 3/2 vs. 2/1 and the answer to the question is NO.
X = 2 and Y=3, then we have 3/4 vs. 2/3 and the answer to the question is YES.
Fact 1 is INSUFFICIENT

2) X < Y

Since X and Y are both POSITIVE, we actually have a rare Number Property rule that we can take advantage of. When dealing with a POSITIVE fraction (meaning a fraction between 0 and 1), adding 1 to both the numerator and denominator will ALWAYS make the resulting fraction BIGGER. For example:
2/3 becomes 3/4 and 3/4 is BIGGER
3/7 becomes 4/8 and 4/8 is BIGGER
1/4 becomes 2/5 and 2/5 is BIGGER
Etc.

Fact 2 tells us that X < Y, so X/Y will be a positive fraction less than 1 and (X+1)/(Y+1) will ALWAYS be greater than X/Y. Thus, the answer to the question is ALWAYS YES.
Fact 2 is SUFFICIENT

Final Answer: B

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