A glucose solution

[boomgoesthegmat]

A glucose solution contains 15 grams of glucose per 100 cubic centimeters of solution. If 45 cubic centimeters of the solution were poured into an empty container, how many grams of glucose would be in the container?

A) 3
B) 5
C) 5.5
D) 6.5
E) 6.75

OA: E

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Hi boomgoesthegmat,

You've been posting large blocks of questions, but you haven't discussed any of YOUR attempt at solving them. Why did you get them wrong? What did you miss? What aspect of each question are you really interested in. It's a good bed that all of these questions have been discussed somewhere online already, so what specifically are you looking for when YOU post them?

This question is ultimately about setting up a ratio. We're told that we have 15 grams of glucose in a 100 cubic cm solution. We're asked how much glucose would be in 45 cubic cm of that solution.

15/100 = X/45

3/20 = X/45

20X = 135

X = 6.75

Final Answer: E

GMAT assassins aren't born, they're made,
Rich

[OptimusPrep]

A glucose solution contains 15 grams of glucose per 100 cubic centimeters of solution. If 45 cubic centimeters of the solution were poured into an empty container, how many grams of glucose would be in the container?

A) 3
B) 5
C) 5.5
D) 6.5
E) 6.75

OA: E

100 cc solution contains 15gm sugar
Hence 1 cc solution will contain 15/100 gm sugar.

Therefore 45 cc solution will contain (15/100)*45 = 6.75 gms Sugar

Correct Option: E

[Jeff@TargetTestPrep]

A glucose solution contains 15 grams of glucose per 100 cubic centimeters of solution. If 45 cubic centimeters of the solution were poured into an empty container, how many grams of glucose would be in the container?

A) 3
B) 5
C) 5.5
D) 6.5
E) 6.75

We are given that a glucose solution contains 15 grams of glucose per 100 cubic centimeters of solution. Since we are dealing with a solution, we know that the grams of glucose is proportional to the number of cubic centimeters of solution. Thus, to determine how many grams of glucose would be in the container when we have 45 cubic centimeters of solution, we can set up a proportion.

We can say: "15 grams of glucose is to 100 cubic centimeters of solution as x grams of glucose is to 45 cubic centimeters of solution." Let's now set up the proportion and solve for x.

15/100 = x/45

Cross multiplying, we obtain:

(15)(45) = 100x

675 = 100x

6.75 = x

There are 6.75 grams of glucose in the solution in the container.

E