Difficulty-wise, I'd place this one in the 600-650 rangeIs (4^-x)(y�) > 0?
1) xy < 0
2) y^x < 0
Cheers,
Brent
Difficulty-wise, I'd place this one in the 600-650 rangeIs (4^-x)(y�) > 0?
1) xy < 0
2) y^x < 0
4^-x is always greater than 0Brent@GMATPrepNow wrote:Here's one I just made up:
Difficulty-wise, I'd place this one in the 600-650 rangeIs (4^-x)(y�) > 0?
1) xy < 0
2) y^x < 0
Cheers,
Brent
I am unable to think of a case when the given stmt would be false.Brent@GMATPrepNow wrote:Yes ...kvcpk wrote: Am I missing something?
Hint: the part in blue is not correct.kvcpk wrote: 4^-x is always greater than 0
y^4 is always greater than 0.
Hence the question always remains true.
We dont need to look at the stmts 1 and 2. Am I missing something?
My Bad. I completely lost track. Y can be zero.Brent@GMATPrepNow wrote:Hint: the part in blue is not correct.kvcpk wrote: 4^-x is always greater than 0
y^4 is always greater than 0.
Hence the question always remains true.
We dont need to look at the stmts 1 and 2. Am I missing something?
Cheers,
Brent
Perfect!kvcpk wrote:My Bad. I completely lost track. Y can be zero.Brent@GMATPrepNow wrote:Hint: the part in blue is not correct.kvcpk wrote: 4^-x is always greater than 0
y^4 is always greater than 0.
Hence the question always remains true.
We dont need to look at the stmts 1 and 2. Am I missing something?
Cheers,
Brent
Ok Now here goes my solution:
As per the given statement, (4^-x)(y^4)>0 gives us YES and (4^-x)(y^4)<=0 gives us NO.
4^-x is always>0
y^4 is always greater than 0 except when y=0
So we get an YES everytime except when y=0
Hence we will need to be looking at our 2 given statements to see if they pose a case of y=0.
stmt 1: xy<0
if xy<0, then either (x<0 and y>0) or (x>0 and y<0)
y cannot be equal to 0.
Hence SUFFICIENT.
Stmt 2: y^x <0
Even here, y cannot be 0, since 0^anything is 0.
Hence SUFFICIENT.
Pick D.
Did i get it right this time Brent?
Here's my solution:Is (4^-x)(y�) > 0?
1) xy < 0
2) y^x < 0