Modems

This topic has expert replies
User avatar
Site Admin
Posts: 2567
Joined: Thu Jan 01, 2009 10:05 am
Thanked: 712 times
Followed by:550 members
GMAT Score:770

Modems

by DanaJ » Thu Nov 18, 2010 12:59 pm
Source: Veritas Prep

A computer store originally bought 1,000 modems at a total cost of d dollars. If each modem was sold for 25 percent more than its original cost, what was the individual price, in terms of d, of each modem sold?

A) d/800
B) 5d/1000
C) 125d
D) d/1000 + 25
E) 125/1000d

User avatar
GMAT Instructor
Posts: 2193
Joined: Mon Feb 22, 2010 6:30 pm
Location: Vermont and Boston, MA
Thanked: 1186 times
Followed by:512 members
GMAT Score:770

by David@VeritasPrep » Thu Nov 18, 2010 1:00 pm
Here is the official Veritas Prep explanation:

Correct answer: (A)

Solution: 1,000 modems cost d dollars, so each modem cost d/1000 dollars. Since the selling price is 25% above the cost, the selling price for each modem is 1.25(d/1000)=5/4(d/1000)=5d/4000=d/800.
Veritas Prep | GMAT Instructor

Veritas Prep Reviews
Save $100 off any live Veritas Prep GMAT Course

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 1179
Joined: Sun Apr 11, 2010 9:07 pm
Location: Milpitas, CA
Thanked: 447 times
Followed by:88 members

by Rahul@gurome » Thu Nov 18, 2010 1:06 pm
DanaJ wrote:A computer store originally bought 1,000 modems at a total cost of d dollars. If each modem was sold for 25 percent more than its original cost, what was the individual price, in terms of d, of each modem sold?
  • A) d/800
    B) 5d/1000
    C) 125d
    D) d/1000 + 25
    E) 125/1000d
Total original cost of 1000 modems = $ d
Original cost of one modem = $ (d/1000)

Individual selling price of each modem = $ (d/1000) + 25% percent of $ (d/1000) = $ (d/1000)*(1 + 25/100) = $ (d/1000)*(1 + 1/4) = $ (d/1000)*(5/4) = $ (d/800)

The correct answer is A.
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)

User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pm
Location: New York, NY
Thanked: 13060 times
Followed by:1906 members
GMAT Score:790

by GMATGuruNY » Thu Nov 18, 2010 1:44 pm
DanaJ wrote:Source: Veritas Prep

A computer store originally bought 1,000 modems at a total cost of d dollars. If each modem was sold for 25 percent more than its original cost, what was the individual price, in terms of d, of each modem sold?

A) d/800
B) 5d/1000
C) 125d
D) d/1000 + 25
E) 125/1000d
Since there is a variable in the answer choices, we can plug in our own value for d.

Let d= 4000.
Cost per modem = 4000/1000 = 4.
Since 25% of 4 = 1, cost increased by 25% = 4+1 = 5. This is our target answer.

Now we plug d=4000 into all the answer choices to see which yields our target of 5.

Only answer choice A works:
d/800 = 4000/800 = 5.

The correct answer is A.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3

Senior | Next Rank: 100 Posts
Posts: 30
Joined: Wed Jan 13, 2010 7:20 am
Thanked: 1 times
Followed by:1 members

by Yes.WeCan » Tue Nov 23, 2010 3:12 pm
My way
25 percent more, so d is modified by 1.25. This could be written as 1.25d/1000 or d/800.

Newbie | Next Rank: 10 Posts
Posts: 1
Joined: Wed Jun 30, 2010 3:40 pm

by Zheni » Tue Dec 07, 2010 7:58 pm
David@VeritasPrep wrote:The above explanations are certainly correct.

Here is the official Veritas Prep explanation:

Correct answer: (A)

Solution: 1,000 modems cost d dollars, so each modem cost d/1000 dollars. Since the selling price is 25% above the cost, the selling price for each modem is 1.25(d/1000)=5/4(d/1000)=5d/4000=d/800.
Hi! Do we know that all 1000 modems were bought at an equal price each? Isn't that supposed to be mentioned in the problem in order to solve it?Thanks!

User avatar
GMAT Instructor
Posts: 2193
Joined: Mon Feb 22, 2010 6:30 pm
Location: Vermont and Boston, MA
Thanked: 1186 times
Followed by:512 members
GMAT Score:770

by David@VeritasPrep » Wed Dec 08, 2010 6:09 am
Certainly that is important, thanks for mentioning it. I will make sure it gets added.

As a practical matter this is what I always tell my students: For Data Sufficiency of course it is an option that you do not have enough information. BUT FOR PROBLEM SOLVING it is not an option that you do not have enough information. So, for example, if the ONLY way to solve is to assume that you have similar triangles, for example, then don't even worry about proving it to yourself because you must get an answer. So if this happens on test day and the only way to solve is for the modems to each be an equal price then just assume they are...for problem solving. Of course, not for data sufficiency.
Veritas Prep | GMAT Instructor

Veritas Prep Reviews
Save $100 off any live Veritas Prep GMAT Course

Junior | Next Rank: 30 Posts
Posts: 23
Joined: Fri Mar 04, 2011 7:04 pm
Thanked: 3 times
Followed by:1 members

by Spidy001 » Thu Apr 14, 2011 5:39 pm
Answer is A.

User avatar
Master | Next Rank: 500 Posts
Posts: 398
Joined: Tue Jul 26, 2011 11:39 pm
Location: India
Thanked: 41 times
Followed by:6 members

by prateek_guy2004 » Sat Aug 06, 2011 11:03 am
This is a great answer to put in values...

Let d be 5000. Total cost d/1000 = 5000/1000 = 5

It is sold after an addition of 25%. So 5* 25/100 = 1.25

After adding 5 + 1.25 = 6.25 This is out target now choose from every answer choises..

Only Answer A Yields 6.25

Master | Next Rank: 500 Posts
Posts: 401
Joined: Tue May 24, 2011 1:14 am
Thanked: 37 times
Followed by:5 members

by MBA.Aspirant » Sat Aug 06, 2011 3:36 pm
d/800

User avatar
Junior | Next Rank: 30 Posts
Posts: 28
Joined: Thu May 19, 2011 8:47 am

by shingik » Fri Aug 19, 2011 8:25 am
1) Determine the cost of each modem = d/1000
2) Determine selling price of each modem = d/1000 * 125% or d/1000 * 125/100
3) Check to see if this is an answer choice---if not simplify further (as you need to do in this case)
4) After simplifying you get d/800 which is A

Step three ---I am not sure if GMAT answers are always in their simplest form but I would not put anything past the GMAC

Master | Next Rank: 500 Posts
Posts: 101
Joined: Thu Aug 25, 2011 9:39 pm

by prashant misra » Mon Oct 03, 2011 5:12 am
oh this was a very easy question but i seem to have done this wrong by picking numbers and did not try for other values.can anyone tell me whether i was right or wrong while substituting values.i supposed d to be 100000 and 1000 items so individual price is 100 but sold for 25% above then each item costs 125 while putting these values i got answer option D but right answer was B when i checked

User avatar
Master | Next Rank: 500 Posts
Posts: 425
Joined: Wed Dec 08, 2010 9:00 am
Thanked: 56 times
Followed by:7 members
GMAT Score:690

by LalaB » Mon Oct 03, 2011 5:39 am
DanaJ wrote:Source: Veritas Prep

A computer store originally bought 1,000 modems at a total cost of d dollars. If each modem was sold for 25 percent more than its original cost, what was the individual price, in terms of d, of each modem sold?

A) d/800
B) 5d/1000
C) 125d
D) d/1000 + 25
E) 125/1000d
1000 modems-d$
1 modem -X$
X=d/1000

since the price is 25% more than the original cost,we just multipy 1.25*d/1000=d/800

User avatar
Master | Next Rank: 500 Posts
Posts: 416
Joined: Tue Aug 30, 2011 2:18 pm
Location: Delhi, India
Thanked: 13 times
Followed by:9 members

by vaibhavgupta » Thu Nov 03, 2011 11:22 am
DanaJ wrote:Source: Veritas Prep

A computer store originally bought 1,000 modems at a total cost of d dollars. If each modem was sold for 25 percent more than its original cost, what was the individual price, in terms of d, of each modem sold?

A) d/800
B) 5d/1000
C) 125d
D) d/1000 + 25
E) 125/1000d
d/1000 = original cost
d/1000*5/4= d/800

Hence A :)
If OA is A, IMO B
If OA is B, IMO C
If OA is C, IMO D
If OA is D, IMO E
If OA is E, IMO A

FML!! :/

Senior | Next Rank: 100 Posts
Posts: 90
Joined: Thu Nov 05, 2009 9:14 am
Thanked: 5 times
Followed by:3 members

by immaculatesahai » Thu Dec 15, 2011 1:12 am
Cost price of each modem= d/1000

Selling price of each modem= 1.25d/1000
= d/800

A wins.