If n is natural number then 6n^2 + 6n is divisible by:

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(a) 6 only
(b) 6 and 12 only
(c) 12 only
(d) by 18 only

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by [email protected] » Thu May 05, 2016 9:35 am
Hi OsMaker,

Are you actually studying for the GMAT? I ask because neither of the questions that you've posted have been GMAT questions. If you're actually studying for the GMAT, then you might want to focus on GMAT-specific practice materials.

As far as this question is concerned, you can use a combination of TESTing VALUES to prove what the calculation is always divisible by. What result do you get when N=1, N=2, N=3, etc?

GMAT assassins aren't born, they're made,
Rich
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