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If a rectangle WXYZ has 240 area and 68 perimeter and A, B,

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If a rectangle WXYZ has 240 area and 68 perimeter and A, B,

by Max@Math Revolution » Thu Feb 18, 2016 6:00 pm
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If a rectangle WXYZ has 240 area and 68 perimeter and A, B, C, D are midpoints, what is the perimeter of a rhombus ABCD?

A. 48
B. 50
C. 52
D. 54
E. 56


* A solution will be posted in two days.
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by Max@Math Revolution » Sun Feb 21, 2016 8:50 pm
If a rectangle WXYZ has 240 area and 68 perimeter and A, B, C, D are midpoints, what is the perimeter of a rhombus ABCD?

A. 48
B. 50
C. 52
D. 54
E. 56


--> In order to satisfy the question that the area is 240 and the perimeter is 68, WX=ZY=24, WZ=XY=10. Then, AX=WA=ZD=DY=12 and XC=CY=WB=BZ=5. AC=CD=DB=BA=13 is derived. So, the perimeter of the rhombus ABCD is 13*4=52.
Therefore, the answer is C.
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