Help w/ Percent ?

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Help w/ Percent ?

by smclean23 » Mon Jul 07, 2008 3:57 pm
Each M-type memory unit will increase the base memory capacity of a certain computer by 3 megabytes. What is the base memory capacity, in megabytes of the computer?
(1) 2 M-type memory units will increase the computers base memory capacity by 300 percent
(2) The memory capacity of the computer after 2 M-type memory units are added to the base memory capacity is 1.6 times the memory capacity of the computer after 1 M-type memory unit is added to the base memory capacity.

Answer is D.
Source: — Data Sufficiency |

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Re: Help w/ Percent ?

by ksh » Tue Jul 08, 2008 8:09 am
smclean23 wrote:Each M-type memory unit will increase the base memory capacity of a certain computer by 3 megabytes. What is the base memory capacity, in megabytes of the computer?
(1) 2 M-type memory units will increase the computers base memory capacity by 300 percent
(2) The memory capacity of the computer after 2 M-type memory units are added to the base memory capacity is 1.6 times the memory capacity of the computer after 1 M-type memory unit is added to the base memory capacity.

Answer is D.
1. 2 M-type memory=6MB
3x=6MB
x=2MB---- sufficient

2. x+6MB=1.6(x+3MB)
0.6x=1.2MB
x=2MB
Sufficient

hence, D

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Re: Help w/ Percent ?

by lunarpower » Fri Jul 11, 2008 2:59 am
the stuff posted by the previous poster is quite accurate, but let's not lose sight of the fact that this is DATA SUFFICIENCY - and that, therefore, a lot of the calculations in that poster's workup are unnecessary.
what follows is the bare minimum of work required to establish the answer to this problem. even if you have no trouble understanding the answer, pay attention to the STOPPING POINT at which you can conclude that each statement is sufficient; it comes earlier than many of you might have thought.
smclean23 wrote: (1) 2 M-type memory units will increase the computers base memory capacity by 300 percent
as the previous poster has recognized, you don't have to treat this as a percentage change problem at all.
just realize that 2 x 3mb, or 6mb, is 300% of the original capacity.
STOP - no need to calculate this value
sufficient
alternatively, if you'd rather treat this problem as a traditional % increase problem, realize that base memory + 6mb is 100% + 300%, or 400%, of base memory itself. letting x stand for base memory, we have x + 6 = 4x.
STOP - no need to solve this equation
sufficient
smclean23 wrote:(2) The memory capacity of the computer after 2 M-type memory units are added to the base memory capacity is 1.6 times the memory capacity of the computer after 1 M-type memory unit is added to the base memory capacity.
x + 6 = 1.6(x + 3)
STOP - no need to solve this equation, especially with those annoying decimals ruining the fun for everyone
sufficient

answer = d

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by the way, i have a hunch that the gmat would be likely to replace "1.6 times" with something requiring an additional step or two, such as "60% greater than" or "8:5 ratio". the current version of statement 2 is just too perfect - the equation practically writes itself.
Ron has been teaching various standardized tests for 20 years.

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