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GMAT Prep - Circles

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Junior | Next Rank: 30 Posts
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by smashinonions » Sat Jun 28, 2008 9:27 pm
total length = pi * r + pi * r + 2 L (distance between the two centers)

total length = 15 (given)

15 = 2 * pi * 0.5 + 2 L

then L = 15 - pi / 2 (ans)
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Five years ago: GMAT - 740

Five years later: 1st Attempt - 620
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Master | Next Rank: 500 Posts
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by rosh26 » Sun Jun 29, 2008 4:12 pm
can you please show where the 2L comes from? I just dont see the distance you are discussing...As far as I see I would subtract L not 2 L.

Thanks.
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Junior | Next Rank: 30 Posts
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by smashinonions » Sun Jun 29, 2008 5:57 pm
The ans is attched. Hope it helps.
Attachments
circlesd.jpg
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Five years ago: GMAT - 740

Five years later: 1st Attempt - 620
GOING for 2nd attempt: Target - 740
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