doubt in solving questions in 1000 ps

[shan_shine007]

can anyone help in solving the following questions in 1000 ps

section 1 - Qn.5

5. At a certain diner, a hamburger and coleslaw cost $3.59, and a hamburger and french fries cost $4.40. If french fries cost twice as much as coleslaw, how much do french fries cost?
(A) $0.30
(B) $0.45
(C) $0.60
(D) $0.75
(E) $0.90

section 1 - Qn.13

13. A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?
(A) 7
(B) 6
(C) 5
(D) 4
(E) 3

[aatech]

h+c = 3.59 ---(1)
h+f = 4.40 ---(2)

f=2c => c=f/2---(3)

Substitute c in (1) from (3)
and solve (1) and (2)

f = 1.62.. Does not look like ans is there..

Are you sure second question is complete? Looks like there is something missing...

[shan_shine007]

13. A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?
(A) 7
(B) 6
(C) 5
(D) 4
(E) 3

[bia]

There are (20x3)/2 = 30 games that that team played.
In order to win at least 3/4 of all its games , they have to win (3/4)x30 ~ 23 games
So, the greatest number of the remaining games that the team can lose is 30-23 = 7 games

Answer is A

[akshatsingh]

section 1 - Qn.5

5. At a certain diner, a hamburger and coleslaw cost $3.59, and a hamburger and french fries cost $4.40. If french fries cost twice as much as coleslaw, how much do french fries cost?
(A) $0.30
(B) $0.45
(C) $0.60
(D) $0.75
(E) $0.90


h+f = 4.40
h+c = 3.59
or
h+2c = 4.40 (since f=2c)
h+c + 3.59

c = 0.81
f = 2c = 1.62



section 1 - Qn.13

13. A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?
(A) 7
(B) 6
(C) 5
(D) 4
(E) 3

I'll just add to what Bia wrote:

There are (20x3)/2 = 30 games that that team played.
In order to win at least 3/4 of all its games , they have to win (3/4)x30 ~ 23 games
So, the greatest number of the remaining games that the team can lose is 30-23 = 7 games

therefore, the greatest number of the "remaining" games that the team can lose = 7 - 3 = 4

Answer is D

[shan_shine007]

Giv d soln for dis ...

Month Average Price per Dozen

April $1.26
May $1.20
June $1.08


19. The table above shows the average (arithmetic mean) price per dozen of the large grade A eggs sold in a certain store during three successive months. If 2/3 as many dozen were sold in April as in May, and twice as many were sold in June as in April, what was the average price per dozen of the eggs sold over the three-month period?
(A) $1.08
(B) $1.10
(C) $1.14
(D) $1.16
(E) $1.18

[akshatsingh]

given on the original thread for this Question

Here it goes again..


A M J
(2/3)X X (4/3)X


Average= {(2/3)X*1.26 + X*1.2 + (4/3)X*1.08}/{(2/3)X+X+(4/3)X}

On solving Average = 1.16

Answer D