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## Variation

tagged by: Brent@GMATPrepNow

This topic has 1 expert reply and 4 member replies
k_suraj786 Newbie | Next Rank: 10 Posts
Joined
22 Apr 2006
Posted:
8 messages

#### Variation

Sat Apr 22, 2006 9:23 am
Elapsed Time: 00:00
• Lap #[LAPCOUNT] ([LAPTIME])
For a finite sequence of non zero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, -3, 2, 5, -4, -6 ?

1. One
2. Two
3. Three
4. Four
5. Five

This is getting really sick....?

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chix475ntu Junior | Next Rank: 30 Posts
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Sat Apr 22, 2006 9:29 am
3 ( 1 * -3 , -3 * 2, 5 * -4)

C

k_suraj786 Newbie | Next Rank: 10 Posts
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Sun Apr 23, 2006 8:02 am
Hey chix475ntu,

Thanks...!!!

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abby_g Junior | Next Rank: 30 Posts
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Sat Sep 30, 2006 2:36 am
1,-3
-3,2
-5,4

hence C

### Top Member

Roland2rule Master | Next Rank: 500 Posts
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Sat Sep 23, 2017 10:06 pm
from the question, we have this (1, -3, 2, 5, -4, -6).
since we are concern with the variation in sign change, we will have the sequence in this form
1,-3 (+ve to -ve)
-3,2 (-ve to +ve)
-5,4 (-ve t +ve)

therefore, we have three variation.
hence,
option C is right

### GMAT/MBA Expert

Brent@GMATPrepNow GMAT Instructor
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Sun Sep 24, 2017 5:16 am
k_suraj786 wrote:
For a finite sequence of non zero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, -3, 2, 5, -4, -6 ?

1. One
2. Two
3. Three
4. Four
5. Five
We're asked to look at every pair of CONSECUTIVE numbers. If the product of that pair is NEGATIVE, this counts as one variation.

Let's examine the pairs of consecutive numbers:

1 and -3: product is negative
-3 and 2: product is negative
2 and 5: product is positive
5 and -4: product is negative
-4 and -6: product is positive

Since 3 pairs have negative products, the correct answer is C

Cheers,
Brent

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