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gmatz Just gettin' started!
Joined: 27 Jul 2007 Posts: 14
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Posted: Tue Aug 28, 2007 11:59 am Post subject: Triangle Problem - Is it possible to solve this? |
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| Is it possible to figure out the area of a triangle with sides of 4,8, and 11? |
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givemeanid Really wants to Beat The GMAT!

Joined: 17 Jun 2007 Posts: 277
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Location: New York, NY
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Posted: Tue Aug 28, 2007 12:06 pm Post subject: Re: Triangle Problem - Is it possible to solve this? |
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| gmatz wrote: | | Is it possible to figure out the area of a triangle with sides of 4,8, and 11? |
Sides = 4, 8 and 11. Lets call them x,y and z
Perimeter = 23
1/2 (Perimeter) = s = 11.5
Area = sqrt (s(s-x)(s-y)(s-z)) = sqrt[11.5 * (11.5 - 4) * (11.5 - 8 ) * (11.5 - 11)] = 12.29 _________________ So It Goes |
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gmatz Just gettin' started!
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Posted: Tue Aug 28, 2007 12:12 pm Post subject: thanks |
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Thanks. Real quickly, what are these relationships called?
1) 1/2 (Perimeter) = s = 11.5
2) Area = sqrt (s(s-x)(s-y)(s-z)) = sqrt[11.5 * (11.5 - 4) * (11.5 - 8 ) * (11.5 - 11)] = 12.29 |
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givemeanid Really wants to Beat The GMAT!

Joined: 17 Jun 2007 Posts: 277
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Location: New York, NY
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Posted: Tue Aug 28, 2007 12:22 pm Post subject: |
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I do not recall the name of the formula. It's been a while since those math classes
If you have a triangle with sides x, y and z, then the area of the triangle is sqrt{s*(s-a)*(s-b)*(s-c)} where s is half the perimeter i.e s = (x+y+z)/2. _________________ So It Goes |
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gmatz Just gettin' started!
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Posted: Tue Aug 28, 2007 12:27 pm Post subject: |
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| thanks |
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gmatz Just gettin' started!
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Posted: Tue Aug 28, 2007 12:39 pm Post subject: It's called Heron's Formula |
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| Just looked it up on the Internet. I'm curious to know where you reviewed this (in a class)? I've never come across this problem during my studies, but just thought of it thinking it could be a problem. |
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