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the value of 1/ [√ (2 x) + √x]?

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sanju09 GMAT Instructor
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the value of 1/ [√ (2 x) + √x]? Fri Mar 23, 2012 4:12 am
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• Lap #[LAPCOUNT] ([LAPTIME])
If x > 0, then what is the value of 1/ [√ (2 x) + √x]?
A. 1/√ (3 x)
B. 1/ [2 √ (2 x)]
C. 1/ (x √2)
D. (√2 - 1)/ √x
E. (1 + √2)/ √x

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mrinal85k Just gettin' started!
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Fri Mar 23, 2012 4:24 am
Answer should be E[/list]

killer1387 GMAT Destroyer!
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Fri Mar 23, 2012 4:55 am
sanju09 wrote:
If x > 0, then what is the value of 1/ [√ (2 x) + √x]?
A. 1/√ (3 x)
B. 1/ [2 √ (2 x)]
C. 1/ (x √2)
D. (√2 - 1)/ √x
E. (1 + √2)/ √x
IMO D

ubhanja Just gettin' started!
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Fri Mar 23, 2012 10:09 am
1/ [√ (2 x) + √x]= 1/√X(√2+1)=(√2-1)/√X(√2+1)(√2-1)=(√2-1)/√X

imo d

sanju09 GMAT Instructor
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Sat Mar 24, 2012 2:31 am
ubhanja wrote:
1/ [√ (2 x) + √x]= 1/√X(√2+1)=(√2-1)/√X(√2+1)(√2-1)=(√2-1)/√X

imo d
perfect

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seal4913 Really wants to Beat The GMAT!
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Sat Mar 24, 2012 12:44 pm
ubhanja wrote:
1/ [√ (2 x) + √x]= 1/√X(√2+1)=(√2-1)/√X(√2+1)(√2-1)=(√2-1)/√X

imo d
Please explain why/how you are getting (√2-1).

pemdas GMAT Titan
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Sat Mar 24, 2012 6:31 pm
seal4913 wrote:
ubhanja wrote:
1/ [√ (2 x) + √x]= 1/√X(√2+1)=(√2-1)/√X(√2+1)(√2-1)=(√2-1)/√X

imo d
Please explain why/how you are getting (√2-1).
there's minor issue, and selected expression must be read as (√2-1)(√2+1)/√X(√2+1)

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