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The sum of 5 different positive 2-digit integers is 130.

This topic has 1 expert reply and 0 member replies

The sum of 5 different positive 2-digit integers is 130.

Post Fri Sep 22, 2017 1:12 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    The sum of 5 different positive 2-digit integers is 130. What is the highest possible value of the largest of these integers?

    A. 88
    B. 84
    C. 78
    D. 74
    E. 68

    What should be my first step in solving this problem? Can experts help me on this?

    OA B

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    Post Fri Sep 22, 2017 1:33 pm
    lheiannie07 wrote:
    The sum of 5 different positive 2-digit integers is 130. What is the highest possible value of the largest of these integers?

    A. 88
    B. 84
    C. 78
    D. 74
    E. 68
    Since the 5 numbers are all different, let's let A, B, C, D and E represent the numbers.
    Furthermore, let's say A < B < C , D < E, which means E is the biggest value.

    We're told that A + B + C + D + E = 130
    In order to MAXIMIZE the value of E, we must MINIMIZE the other 4 values.
    In other words, we want to MINIMIZE the value of A + B + C + D
    Since the numbers must be 2-digit integers, the smallest values for A, B, C and D are 10, 11, 12 and 13 respectively.

    So, plugging those values into our equation, we get: 10 + 11 + 12 + 13 + E = 130
    Simplify: 46 + E = 130
    E = 84

    Answer: B

    Cheers,
    Brent

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