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The ratio of the length (OG16)

This topic has 2 expert replies and 0 member replies
boomgoesthegmat Senior | Next Rank: 100 Posts Default Avatar
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The ratio of the length (OG16)

Post Thu May 19, 2016 3:44 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    The ratio of the length to the width of a rectangular advertising display is approximately 3.3 to 2. If the width of the display is 8 meters, what is the approximate length of the display, in meters?

    A) 7
    B) 11
    C) 13
    D) 16
    E) 26

    OA: C

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    Post Thu May 19, 2016 4:12 pm
    boomgoesthegmat wrote:
    The ratio of the length to the width of a rectangular advertising display is approximately 3.3 to 2. If the width of the display is 8 meters, what is the approximate length of the display, in meters?

    A) 7
    B) 11
    C) 13
    D) 16
    E) 26

    OA: C
    This is a matter of EQUIVALENT RATIOS:
    length/width: 3.3/2 = x/8

    Approach #1: Notice that the width increases by a factor of 4 (from 2 to 8)
    So, the length must increase be a factor of 4 as well.
    3.3(4) = 13.2

    Answer: C

    --------------------------------
    Approach #2
    3.3/2 = x/8
    Cross multiply: (3.3)(8) = (2)(x)
    Evaluate: 26.4 = 2x
    Solve: x = 13.2

    Answer: C

    -------------------

    RELATED RESOURCE (video)
    - Intro to ratios: https://www.gmatprepnow.com/module/gmat-arithmetic/video/1081

    Cheers,
    Brent

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    Post Thu May 19, 2016 4:15 pm
    Hi boomgoesthegmat,

    This question gives us a ratio and asks us for the APPROXIMATE length of a display. The given ratio of length:width is 3.3:2 and the width is 8 meters. Since 8 is 4 times 2, the actual measurements of the length and width are (4)(3.3) and (4)(2) respectively (that gives us a length of 13.2 and a width of 8).

    Final Answer: C

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