test20 #20

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test20 #20

by dunkin77 » Wed May 02, 2007 6:54 pm
Hi,

I thought the answer was B) but it says C)..... Can anyone help?
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by jayhawk2001 » Wed May 02, 2007 8:04 pm
Hmm, I can't see how the answer can be C.

Using 2, we get x^2 -1 < 0 which implies -1 < x < 1

If x^2-1 < 0, in (1), 1-x^2 is positive and so n has to be negative.

1 and 2 combined, -1 < x < 1. So, we can't say for sure if
x is positive or negative.

Am I missing something?