Free GMAT Flashcards available for download!

Test Prep2


 
Post new topic   Reply to topic    Beat The GMAT Forum Index -> GMAT Math -> Problem Solving
View previous topic :: View next topic  
Author Message
moneyman
GMAT Destroyer!


Joined: 03 Mar 2007
Posts: 467

Thanks given: 3
Thanked 5 times in 5 posts


PostPosted: Sun Mar 16, 2008 6:41 am    Post subject: Test Prep2 Reply with quote

M=(4)^1/2+(4)1/3+(4)1/2 what is the value of M??

Greater than 3
Equal to 3
Between 3 and 4
Equal to 4
Greater than 4

The answer is E

_________________
Maxx
Back to top


View user's profile Send private message
camitava
GMAT Destroyer!


Joined: 05 Sep 2007
Posts: 633

Thanks given: 3
Thanked 26 times in 26 posts

Location: India

PostPosted: Sun Mar 16, 2008 8:39 am    Post subject: Re: Test Prep2 Reply with quote

moneyman wrote:
M=(4)^1/2+(4)1/3+(4)1/2 what is the value of M??

Greater than 3
Equal to 3
Between 3 and 4
Equal to 4
Greater than 4

The answer is E


Look, M=(4)^1/2+(4)1/3+(4)1/2
or M = 2 + 4/3 + 2 = 4 + 4/3
So M > 4
So go for E.

_________________
Correct me If I am wrong


Regards,

Amitava
Back to top


View user's profile Send private message
musicdaemon
Just gettin' started!


Joined: 13 Feb 2008
Posts: 27

Thanks given: 0
Thanked 1 times in 1 posts

Location: India
Target GMAT Score: 730

PostPosted: Sun Mar 16, 2008 9:58 pm    Post subject: Re: Test Prep2 Reply with quote

camitava wrote:
moneyman wrote:
M=(4)^1/2+(4)1/3+(4)1/2 what is the value of M??

Greater than 3
Equal to 3
Between 3 and 4
Equal to 4
Greater than 4

The answer is E


Look, M=(4)^1/2+(4)1/3+(4)1/2
or M = 2 + 4/3 + 2 = 4 + 4/3
So M > 4
So go for E.


Sorry to disagree with you Amitava, here is my dig at it :

M=(4)^1/2+(4)1/3+(4)1/2

Now, (4)^1/2 = +2 or -2

if it is +2 then your solution is correct,

if it is -2, then

M= 4/3 = 1.33

this choice is not provided. Thus the question is ambiguous

_________________
Let the Game begin
Back to top


View user's profile Send private message
camitava
GMAT Destroyer!


Joined: 05 Sep 2007
Posts: 633

Thanks given: 3
Thanked 26 times in 26 posts

Location: India

PostPosted: Sun Mar 16, 2008 10:15 pm    Post subject: Reply with quote

Hey musicdaemon, what a catch man! Good catch, indeed! But I would like to say here that generally this type of ambiguous Qs are not asked in GMAT. I agree I missed the issue mentioned by u ...
_________________
Correct me If I am wrong


Regards,

Amitava
Back to top


View user's profile Send private message
smushkas
Rising GMAT Star


Joined: 01 Jul 2007
Posts: 49

Thanks given: 20
Thanked 3 times in 3 posts


PostPosted: Mon Mar 17, 2008 8:53 am    Post subject: Reply with quote

Hey guys,

Just a quick comment. Original question was like, see the link, please.

http://www.beatthegmat.com/gmatprep-ps-t9183.html#36723
Back to top


View user's profile Send private message Send e-mail
musicdaemon
Just gettin' started!


Joined: 13 Feb 2008
Posts: 27

Thanks given: 0
Thanked 1 times in 1 posts

Location: India
Target GMAT Score: 730

PostPosted: Mon Mar 17, 2008 10:14 am    Post subject: Reply with quote

smushkas wrote:
Hey guys,

Just a quick comment. Original question was like, see the link, please.

http://www.beatthegmat.com/gmatprep-ps-t9183.html#36723



Smushkas,

even then squrt(4)= +2 or -2
and the answer choices are ambiguous. Isn't it?

_________________
Let the Game begin
Back to top


View user's profile Send private message
camitava
GMAT Destroyer!


Joined: 05 Sep 2007
Posts: 633

Thanks given: 3
Thanked 26 times in 26 posts

Location: India

PostPosted: Mon Mar 17, 2008 10:40 am    Post subject: Reply with quote

musicdaemon wrote:
smushkas wrote:
Hey guys,

Just a quick comment. Original question was like, see the link, please.

http://www.beatthegmat.com/gmatprep-ps-t9183.html#36723



Smushkas,

even then squrt(4)= +2 or -2
and the answer choices are ambiguous. Isn't it?

Actually musicdaemon, sqrt(x) is always positive and it can not be negative.

_________________
Correct me If I am wrong


Regards,

Amitava
Back to top


View user's profile Send private message
musicdaemon
Just gettin' started!


Joined: 13 Feb 2008
Posts: 27

Thanks given: 0
Thanked 1 times in 1 posts

Location: India
Target GMAT Score: 730

PostPosted: Mon Mar 17, 2008 8:18 pm    Post subject: Reply with quote

Amitava,
I guess My basics in quant are still in place.

Sqrt of any number will have two values one -ve and one +ve

apply the reverse logic:

(-2)^2 = 4 & (2)^2 =4

Take sqrt on both sides now,

-2=sqrt(4) & 2 = sqrt(4)

Thus, sqrt(4) = +2 and -2


Prove me wrong!!!

_________________
Let the Game begin
Back to top


View user's profile Send private message
camitava
GMAT Destroyer!


Joined: 05 Sep 2007
Posts: 633

Thanks given: 3
Thanked 26 times in 26 posts

Location: India

PostPosted: Mon Mar 17, 2008 8:41 pm    Post subject: Reply with quote

musicdaemon wrote:
Amitava,
I guess My basics in quant are still in place.

Sqrt of any number will have two values one -ve and one +ve

apply the reverse logic:

(-2)^2 = 4 & (2)^2 =4

Take sqrt on both sides now,

-2=sqrt(4) & 2 = sqrt(4)

Thus, sqrt(4) = +2 and -2


Prove me wrong!!!

Musicdaemon,
I agree with ur point partially. I said sqrt(x) should always be positive. But \/-x can be both positive and negative. Got me, MusicDaemon? If you search this PS forum, u will find that this issue has already been discussed. And still if u r having any doubt, u can ask Stuart to help.

_________________
Correct me If I am wrong


Regards,

Amitava
Back to top


View user's profile Send private message
musicdaemon
Just gettin' started!


Joined: 13 Feb 2008
Posts: 27

Thanks given: 0
Thanked 1 times in 1 posts

Location: India
Target GMAT Score: 730

PostPosted: Mon Mar 17, 2008 8:54 pm    Post subject: Reply with quote

Amitava,
I don't have an iota of doubt on this.

The answer choices for this question are ambiguous.

_________________
Let the Game begin
Back to top


View user's profile Send private message
gabriel
Managing Director


Joined: 20 Dec 2006
Posts: 872

Thanks given: 121
Thanked 27 times in 26 posts

Location: India

PostPosted: Mon Mar 17, 2008 10:29 pm    Post subject: Reply with quote

Actually Amitava is right, the sqrt of a number until unless mentioned should be considered positive. While you are right that any integer has 2 roots, we consider only the positive root (the principal root) for solving problems such as these. So Amitava's answer is right i.e m>4. There is no ambiguity in the answer choices.

Do a google search on "principal square root" and you will find articles on why this is so.

Regards


Last edited by gabriel on Mon Mar 17, 2008 11:47 pm; edited 1 time in total
Back to top


View user's profile Send private message
resilient
GMAT Destroyer!


Joined: 06 May 2007
Posts: 789

Thanks given: 21
Thanked 5 times in 5 posts

Location: Southern California, USA
Target GMAT Score: 710

PostPosted: Mon Mar 17, 2008 11:44 pm    Post subject: clarification Reply with quote

FIrst, all you guys are great at catching such subtle details. I am a bit confused now, I see Mr. Daemon's point but see moderators point also. For the sake of the exam, are we considering all roots positive? I believe this is what is taught in the manhattan gmat book also.

AS for the original question, I think the original poster is hurting from understanding that all fractional exponents are treated as roots. I had to make a flash card on this to commit it to memory. Recommendations to you also.

_________________
Appetite for 700 and I scraped my plate!
Back to top


View user's profile Send private message
gabriel
Managing Director


Joined: 20 Dec 2006
Posts: 872

Thanks given: 121
Thanked 27 times in 26 posts

Location: India

PostPosted: Mon Mar 17, 2008 11:52 pm    Post subject: Re: clarification Reply with quote

Enginpasa1 wrote:
FIrst, all you guys are great at catching such subtle details. I am a bit confused now, I see Mr. Daemon's point but see moderators point also. For the sake of the exam, are we considering all roots positive? I believe this is what is taught in the manhattan gmat book also.

AS for the original question, I think the original poster is hurting from understanding that all fractional exponents are treated as roots. I had to make a flash card on this to commit it to memory. Recommendations to you also.


It is not just for GMAT, but for math in general we consider only the principal roots that is the positive roots of any real number. There are many reasons for this e.g. use of square roots in the Pythagoras theorem.

Regards
Back to top


View user's profile Send private message
musicdaemon
Just gettin' started!


Joined: 13 Feb 2008
Posts: 27

Thanks given: 0
Thanked 1 times in 1 posts

Location: India
Target GMAT Score: 730

PostPosted: Tue Mar 18, 2008 12:20 am    Post subject: Reply with quote

Gabriel,
For discreet values given as choices, of simple functions, we can use the principle sq root. But, when the range of values is required then you may have to use both the values. And that is what is the case in the given problem.

i guess we have to get it by heart - to use +ve root for GMAT unless required specifically.

_________________
Let the Game begin
Back to top


View user's profile Send private message
suman2424
Just gettin' started!


Joined: 19 Feb 2008
Posts: 9

Thanks given: 0
Thanked 0 times in 0 posts


PostPosted: Wed Mar 19, 2008 11:20 am    Post subject: Reply with quote

Yes by convention, sqrt(x) is always positive. Because of this, the answer must be greater than 4.
Back to top


View user's profile Send private message
Display posts from previous:   
Post new topic   Reply to topic    Beat The GMAT Forum Index -> GMAT Math -> Problem Solving All times are GMT - 8 Hours
Page 1 of 1

 
Jump to:  
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot vote in polls in this forum
You cannot attach files in this forum
You cannot download files in this forum



"GMAT" and other GMAC™ trademarks are registered trademarks of the Graduate Management Admission Council™. The Graduate Management Admission Council™ does not endorse, nor is it affiliated in any way with the owner or any content on this website. The opinions expressed here are solely those of the author or those of the members of this website. Copyright © 2009 BTG Test Prep, LLC. Powered by phpBB.