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test 13 #12

This topic has 4 member replies
dunkin77 Master | Next Rank: 500 Posts Default Avatar
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test 13 #12

Post Mon Apr 23, 2007 2:23 pm
Elapsed Time: 00:00
  • Lap #[LAPCOUNT] ([LAPTIME])
    12. In a sequence of numbers in which each term after the first term is 1 more than twice the preceding term, what is the fifth term?

    (1) The first term is 1.
    (2) The sixth term minus the fifth term is 32.

    Hi,

    I thoght the question is x, 2x+1, 2(2x+1)+1, ..... and chose D), but the correct answer is B) -- Can anyone please explain??

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    mschling52 Master | Next Rank: 500 Posts Default Avatar
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    Post Thu Apr 26, 2007 9:47 am
    I agree with you on D...Seems like (1) allows you to construct the sequence, since a1 = 1 we have

    1, 3, 7, 15, 31, ..... and a5 = 31

    (2) gives us

    a6 - a5 = 32
    2a5 + 1 - a5 = 32
    a5 = 31

    So, I agree that each alone is sufficient, but maybe I am missing something as to why (1) isn't.

    f2001290 Master | Next Rank: 500 Posts
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    Post Thu Apr 26, 2007 8:47 pm
    I agree with both of you . It should be D.



    Last edited by f2001290 on Wed May 16, 2007 9:53 pm; edited 1 time in total

    arielsky Newbie | Next Rank: 10 Posts Default Avatar
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    Post Sun Apr 29, 2007 4:30 am
    sorry...can someone explain why it wouldnt be C? how do we know where to start off if we arent given the first term?

    arielsky Newbie | Next Rank: 10 Posts Default Avatar
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    Post Sun Apr 29, 2007 4:32 am
    oh wait sorry, i got confused, choice c always states that both of them together are useful but each alone is not, which isnt the case here.

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