Teneka and Francis leave Town A at 9:00 a.m. driving north along Highway B, in seperate cars. Teneka drives 30 miles per hour and Francis drives 40 miles per hour. If after traveling 240 miles Francis' car breaks down and stops, at what time will Teneka's car reach Francis' car?
A. 11 p.m.
B. 10 p.m.
C. 6 p.m.
D. 5 p.m.
E. 3 p.m.
The OA is D.
Can someone make a graph of the vehicles so I can understand it better. Please.
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Teneka and Francis leave Town A at 9:00 a.m. driving...
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Given: Francis drives 240 miles and then stops (breaks down)Vincen wrote:Teneka and Francis leave Town A at 9:00 a.m. driving north along Highway B, in seperate cars. Teneka drives 30 miles per hour and Francis drives 40 miles per hour. If after traveling 240 miles Francis' car breaks down and stops, at what time will Teneka's car reach Francis' car?
A. 11 p.m.
B. 10 p.m.
C. 6 p.m.
D. 5 p.m.
E. 3 p.m.
So, Teneka will reach Francis once Teneka drives 240 miles.
How long will it take Teneka to drive 240 miles?
Time = distance/speed = (240 miles)/(30 miles per hour) = 8 hours
Teneka started driving at 9:00am
So, after 8 hours, the time will be 5pm
Answer: D
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Jeff@TargetTestPrep
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Since distance/rate = time and 240/30 = 8, Taneka had to drive 8 hours to reach Francis.Vincen wrote:Teneka and Francis leave Town A at 9:00 a.m. driving north along Highway B, in seperate cars. Teneka drives 30 miles per hour and Francis drives 40 miles per hour. If after traveling 240 miles Francis' car breaks down and stops, at what time will Teneka's car reach Francis' car?
A. 11 p.m.
B. 10 p.m.
C. 6 p.m.
D. 5 p.m.
E. 3 p.m.
The OA is D.
So, she reached Francis at 9 a.m. + 8 hours = 5 p.m.
Answer: D
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