| View previous topic :: View next topic |
| Author |
Message |
syv11
Rising GMAT Star
Joined: 23 Nov 2007
Posts: 46
Thanks given: 0
Thanked 0 times in 0 posts
|
 Posted: Sat Dec 01, 2007 6:01 pm Post subject: Straight Math |
 |
|
If -1/2<=x<=-1/3 and -1/4<=y<=-1/5 what is the minimum value of xy^2?
A -1/75
B -1/50
C -1/78
D -1/32
E -1/16 |
|
| Back to top |
|
 |
|
|
seekmba
Just gettin' started!
Joined: 20 Sep 2007
Posts: 28
Thanks given: 0
Thanked 4 times in 4 posts
|
| Posted: Sun Dec 02, 2007 7:49 am Post subject: |
|
|
I think the ans is D =1/32
xy^2 = -1/2*-1/4^2 = -1/32
Whats the OA? |
|
| Back to top |
|
|
newmikeyork
Just gettin' started!
Joined: 27 Nov 2007
Posts: 19
Thanks given: 0
Thanked 1 times in 1 posts
Location: Canada, eh
Test Date: Dec 7 - Three Days!
Target GMAT Score: 750
|
| Posted: Mon Dec 03, 2007 7:42 pm Post subject: |
|
|
I would go with B: -1/50.
Smallest x is -1/2
Smallest y is 1/25 (-1/5)^2 |
|
| Back to top |
|
|
|
